Half-Wave Rectifier

Half-Wave Rectifier - Half-Wave Rectifier Ideal diode model...

Info iconThis preview shows pages 1–3. Sign up to view the full content.

View Full Document Right Arrow Icon
© Bob York, 2006-2009 Back to TOC Half-Wave Rectifier V out V in V out V in Constant voltage drop model Diode conducts only for positive input voltages. An AC input with zero average yields a non-sinusoidal output with a non-zero DC component. The conversion of AC to DC is called rectification. The “conduction angle” θ c is that part of the cycle during which the diode is conducting. The average DC component is given by T Ideal diode model θ c 0 1 () T dc VV t d t T V dc V dc d v V out V in
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
© Bob York, 2006-2009 Back to TOC Half-Wave Rectifier Assume constant voltage drop model θ c  0 2 2 11 () s in 1 2 off on Tt dc out m d t md c d mm VV t d t V t v d t TT Vv v       d v V out V in T s in m Vt V t 0o t h e r w i s e in d in d out Vt v V v Vt  1 sin d on m v t V    1 sin d off m v t V  1 2 s i n d co f f o n m v tt V  Conduction Angle 2 for d cd m m v vV V
Background image of page 2
Image of page 3
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 03/17/2010 for the course ECE 2B taught by Professor York during the Winter '07 term at UCSB.

Page1 / 6

Half-Wave Rectifier - Half-Wave Rectifier Ideal diode model...

This preview shows document pages 1 - 3. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online