PS_6%20soln - ChBE 421 Problem Set#6 Solution Fall 2009 1...

This preview shows pages 1–2. Sign up to view the full content.

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: ChBE 421 Problem Set #6 Solution Fall 2009 1. The variables involved are: ρ , μ , σ , D , v , e Using the Buckingham theorem, we will get 3 different dimensionless groups. Since the problem gives relations for ρ , μ and σ , we’ll use these as the core variables. Hence, 1 2 3 a b c a b c a b c D v e π ρ μ σ π ρ μ σ π ρ μ σ = = = Solving for each a , b and c and applying the numbers gives 1 2 2 3 2 D v e ρσ π μ μ π σ ρσ π μ = = = These terms should be equal for the case of water and the actual application. If we denote 2 H O D xD = , 2 H O v yv = , 2 H O e ze = , 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 H O H O H O H O H O H O 2 2 2 2 H O H O H O H O H O H O H O H O H O H O H O H O H O H O 2 2 2 2 H O H O 1.8 2.1 2.1 1.8 1.8 2.1 xD D D v yv v ze e e ρ σ ρ σ ρσ μ μ μ μ μ μ σ σ σ ρ σ ρ σ ρσ μ μ μ × × = = × = = × × = = Solving for x, y, z, we get 2 2 2.1 2.45 1.8 1.8 0.857 2.1 2.1 2.45 1.8 x y z = = = = = = and therefore, 2 H O 2.452....
View Full Document

{[ snackBarMessage ]}

Page1 / 4

PS_6%20soln - ChBE 421 Problem Set#6 Solution Fall 2009 1...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online