advgeneansw - 10 f. Yes g. 1 2 9 h. I1: RE, re 8. a. ZZ ZZ...

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Biol 215 Advanced Genetics Advanced Genetics Answers 1. SSCC × sscc F1 SsCc ScCcc × sscc a. Plump, color × Shrunken, colorless b. SC, sc c. 301 8369 " 100 = 3 . 6 units 2. RrNn × rrnn Expected RN Rn rN rn rn 99.75 99.75 99.75 99.75 Actual RN Rn rN rn rn 124 77 72 126 RN, rn linked: 149 399 " 100 = 37 units 3. A B | | C? C? 14.5 7 7 Need crossover frequency between AC to determine position of C. 4. JMLKN | | | 70 20 J M L K N 50 15 30 35 15 149
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Biol 215 Advanced Genetics 5. Straight, blue × twisted, green S/_G/_ × ssgg SsGg SsGg × ssgg Expected SG sG Sg sg sg 475 475 475 475 Actual SG sG Sg sg sg 855 95 95 855 RN, rn linked: 190 1900 × 100 = 10 units 6. No; independent assortment could occur 50% of the time. 7. a. = E/_ =ee b. re: II1. II2, III6 RE: II5, II9. III2-5,7 c. All 10 d. 5 each e. 1 2
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Unformatted text preview: 10 f. Yes g. 1 2 9 h. I1: RE, re 8. a. ZZ ZZ ZZ b. XY XY 1 female : 3 males c. YY males are viable. Looks like males regularly mate with males. d. XX XX XX, all females e. YY exists. See the pedigree to the right. 9. 2n=16= a. 8 b. 0 c. 8 10. a, 1 2 =0.5= b. 2 2 =1.0= c. 2 3 =0.67=intersex O O O 190 XY XY XY YY XX XX 198 sons, XY Biol 215 Advanced Genetics d. 2 2 =1.0= e. 3 2 =1.5=superfemale f. 3 3 =1.0= g. lethal 11. a. all b. none c. 1:1 12. FfXX FFXY daughters long, daughters short. All sons short. The rules: Male Female FF Short Short Ff Short Long ff Long Long The Punnett Square: FX fX FX FY O O...
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advgeneansw - 10 f. Yes g. 1 2 9 h. I1: RE, re 8. a. ZZ ZZ...

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