chapter2hw - CHAPTER 2 THE COMPONENTS OF MATTER 2.1 Plan:...

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2-1 CHAPTER 2 THE COMPONENTS OF MATTER 2.1 Plan: Refer to the definitions of an element and a compound. Solution: Unlike compounds, elements cannot be broken down by chemical changes into simpler materials. Compounds contain different types of atoms; there is only one type of atom in an element. 2.5 Some elements, such as the Noble gases (He, Ne, Ar, etc.) occur as individual atoms. Many other elements, such as most other nonmetals (O 2 , N 2 , S 8 , P 4 , etc.) occur as molecules. 2.7 Mixtures have variable composition; therefore, the amounts may vary. Compounds, as pure substances, have constant composition, thus their composition cannot vary. 2.8 The tap water must be a mixture, since it consists of some unknown (and almost certainly variable) amount of dissolved material in solution in water. 2.10 If you have no reliable way of determining the composition of a sample, you have no hope of knowing if its composition is constant. 2.15 Generally no, the composition of a compound is determined by the elements used, not their amounts. If too much of one element is used, the excess will remain as unreacted element when the reaction is over. 2.17 These two experiments demonstrate the Law of Definite Composition. In both cases, the ratio of (g Cu reacted)/(g I reacted) is 0.50, so the composition is constant regardless of the method of preparation. They also demonstrate the Law of Conservation of Mass, since in both cases the total mass before reaction equals the total mass after reaction. 2.19 a) 2.34 g compound - 2.03 g lead = 0.31 g sulfur b) Mass fraction Pb = 2.03/2.34 = 0.86752 = 0.868 Mass fraction S = 0.31/2.34 = 0.13248 = 0.13 c) Mass % Pb = 0.868 fraction x 100 = 86.752 = 86.8% Mass % S = 0.13 fraction x 100 = 13.248 = 13% 2.23 Mass of compound = 63.94 g cesium + 61.06 g iodine = 125.00 g compound Mass of cesium = () 63.94 g cesium 38.77 g 125.00 g compound ⎛⎞ ⎜⎟ ⎝⎠ = 19.83163 = 19.83 g cesium Mass of iodine = 61.06 g iodine 38.77 g 125.00 g compound = 18.9384 = 18.94 g iodine 2.25 Compound 1: 77.6 mass % Xe 22.4 mass % F = 3.4643 = 3.46 Compound 2: 63.3 mass % Xe 36.7 mass % F = 1.7248 = 1.72 Ratio: 72 . 1 46 . 3 = 2.0116 = 2.01 / 1.00 The ratios are in a 2:1 ratio, supporting the Law of Multiple Proportions.
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This note was uploaded on 03/18/2010 for the course CHEM 210 taught by Professor Mcomber during the Spring '10 term at Skyline College.

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chapter2hw - CHAPTER 2 THE COMPONENTS OF MATTER 2.1 Plan:...

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