chem lab exp. 5

chem lab exp. 5 - Laboratory 5 Decomposition of Compounds...

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Laboratory 5 Decomposition of Compounds and Determination of Percent by Mass Name: Norkhairin Yusuf Partner: Azizah Ahmad Section Section 40, Monday 2 PM Performed: 06 October, 2008 Submitted 13 October, 2008 Laboratory Instructor: Hongmei Yuan Your Signature ___________________________________
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Useful equations NaHCO 3 (s) + heat a NaOH(s) + CO 2 (g) 2 NaHCO 3 (s) + heat a 2 Na(s) + CO 2 (g) + H 2 O 2 (g) 2 NaHCO 3 (s) + heat a Na 2 O(s) + 2 CO 2 (g) + H 2 O(g) Purpose The purpose of this lab was to look at the effect of how compounds that are chemically combined elements which can be decomposed to form original elements or to form other compounds or combinations of both element and compounds. Introduction One category of compounds binds water molecules when formed and they lose water molecules easily upon heating. These are called hydrates and have formulas recognized by a number of water molecules placed after the compound’s formula, separated by a dot. So for this experiment Magnesium Sulfate is used for the hydrate salt. The non-hydrated salt is called an anhydrous salt . Very often, there is a distinct difference between the two compounds. If the formula of the hydrate is known, the percent by mass of water can be calculated directly: ___total mass of water___ X 100 = % water (by mass) total mass of hydrated salt If the formula of the hydrate is unknown, the percent by mass of water can be determined experimentally, by weighing the hydrated salt before and after heating: _____total mass loss_____ X 100 = % water (by mass)
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This note was uploaded on 03/18/2010 for the course COS 101121501 taught by Professor Langner during the Fall '08 term at RIT.

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chem lab exp. 5 - Laboratory 5 Decomposition of Compounds...

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