ch07-p053 - part (a) by 0.013 yields about ten million...

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53. (a) We set up the ratio 50 1 13 km 1 km megaton = F H G I K J E / and find E = 50 3 1 × 10 5 megatons of TNT. (b) We note that 15 kilotons is equivalent to 0.015 megatons. Dividing the result from
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Unformatted text preview: part (a) by 0.013 yields about ten million bombs....
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