(98 N)(0.040 m)3.9 J.WFd=⋅==GG(d) Since the force of gravity GFg(with magnitude mg) is opposite to the displacement Gdc=0 020.m (up) of the canister, Eq. 7-7 leads to (196 N)(0.020 m)3.9 J.gcWFd−=−GGThis is consistent with Eq. 7-15 since there is no change in kinetic energy. 57. There is no acceleration, so the lifting force is equal to the weight of the object. We note that the person’s pull GFis equal (in magnitude) to the tension in the cord. (a) As indicated in the
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This note was uploaded on 03/19/2010 for the course PHYSICS 191262 taught by Professor Najafzadeh during the Spring '09 term at The Petroleum Institute.