ch07-p060 - 60. The acceleration is constant, so we may use...

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60. The acceleration is constant, so we may use the equations in Table 2-1. We choose the direction of motion as + x and note that the displacement is the same as the distance traveled, in this problem. We designate the force (assumed singular) along the x direction acting on the m = 2.0 kg object as F . (a) With v 0 = 0, Eq. 2-11 leads to a = v / t . And Eq. 2-17 gives Δ xv t 1 2 = . Newton’s second law yields the force F = ma . Eq. 7-8, then, gives the work:
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