60. The acceleration is constant, so we may use the equations in Table 21. We choose
the direction of motion as +
x
and note that the displacement is the same as the distance
traveled, in this problem. We designate the force (assumed singular) along the
x
direction
acting on the
m
= 2.0 kg object as
F
.
(a) With
v
0
= 0, Eq. 211 leads to
a
=
v
/
t
. And Eq. 217 gives
Δ
xv
t
1
2
=
. Newton’s
second law yields the force
F
=
ma
. Eq. 78, then, gives the work:
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This note was uploaded on 03/19/2010 for the course PHYSICS 191262 taught by Professor Najafzadeh during the Spring '09 term at The Petroleum Institute.
 Spring '09
 NAJAFZADEH
 mechanics, Acceleration, Force

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