ch07-p061 - P = Fv = (6.60 × 10 4 )(150 m/60.0 s) = 1.65...

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61. The total weight is (100)(660 N) = 6.60 × 10 4 N, and the words “raises … at constant speed” imply zero acceleration, so the lift-force is equal to the total weight. Thus
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Unformatted text preview: P = Fv = (6.60 × 10 4 )(150 m/60.0 s) = 1.65 × 10 5 W....
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This note was uploaded on 03/19/2010 for the course PHYSICS 191262 taught by Professor Najafzadeh during the Spring '09 term at The Petroleum Institute.

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