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KK
W
Kx
xx
x
x f
f
ff
−=
−
−
<<
33
12
4
30
()
(
.
)
so that the requirement
8.0 J
xf
K
=
leads to
x
f
=
40
. m
.
(c) As long as the work is positive, the kinetic energy grows. The graph shows this
situation to hold until
x
= 1.0 m. At that location, the kinetic energy is
100
1
16 J 2.0 J 18 J.
x
KKW
=+
=
+
=
66. From Eq. 732, we see that the “area” in the graph is equivalent to the work done. We
find the area in terms of rectangular [length
×
width] and triangular [
1
2
base
×
height]
areas and use the workkinetic energy theorem appropriately. The initial point is taken to
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This note was uploaded on 03/19/2010 for the course PHYSICS 191262 taught by Professor Najafzadeh during the Spring '09 term at The Petroleum Institute.
 Spring '09
 NAJAFZADEH
 mechanics, Energy, Kinetic Energy, Work

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