ch07-p069 - 69(a Eq 7-6 gives Wa = Fd =(209 N(1.50 m 314...

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69. (a) Eq. 7-6 gives W a = Fd = (209 N)(1.50 m) 314 J. (b) Eq. 7-12 leads to W g = (25.0 kg)(9.80 m/s 2 )(1.50 m)cos(115º) –155 J. (c) The angle between the normal force and the direction of motion remains 90º at all
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This note was uploaded on 03/19/2010 for the course PHYSICS 191262 taught by Professor Najafzadeh during the Spring '09 term at The Petroleum Institute.

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