ch07-p078 - For the interested student it might be...

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78. The problem indicates that SI units are understood, so the result (of Eq. 7-23) is in Joules. Done numerically, using features available on many modern calculators, the result is roughly 0.47 J.
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Unformatted text preview: For the interested student it might be worthwhile to quote the “exact” answer (in terms of the “error function”): ´ 1.2 ¶ .15 e-2 x² dx = ¼ 2 π [ erf(6 2 /5) – erf(3 2 /20) ] ....
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This note was uploaded on 03/19/2010 for the course PHYSICS 191262 taught by Professor Najafzadeh during the Spring '09 term at The Petroleum Institute.

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