math dq1 week 3

# math dq1 week 3 - to an equation It is possible to replace...

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Solving a linear inequality is quite the same as solving a linear equation . The one main difference between the two is one small but very important detail. You flip the inequality sign whenever you multiply or divide the inequality by a negative. To determine if the value for the solution is correct one would need to substitute the value for the variable. One would need to do whatever arithmetic is necessary to see if you have a true statement. If the statement is true, the value is an element of the solution set. If the statement is false, it is not an element of the solution set. The method is basically the same when it comes to determining if a value is a solution

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Unformatted text preview: to an equation. It is possible to replace the equal sign of an equation with an inequity sign. Even doing this there are times the solution could be the same for both. Normally this is the case when the equal sign in the equation is replaced with the greater or lesser than sign which is given within an inequality problem. 20/5 –x >-15 10-23y › 56 10- 10 = -23y 56- 10 = 46 46-23y › 46 To divide y by 1 The y just gets copied along in the numerator. The answer is y-23y ÷ -23 = y 46 ÷ -23 = -2 N + N = 2N 2N+2 2N+2 ‹ 20 2- 2 = 2N 20- 2 = 18 18 2N ‹ 18 2N ÷ 2 = N 18 ÷ 2 = 9 N ‹ 9...
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math dq1 week 3 - to an equation It is possible to replace...

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