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/
/
ff
λτ
μ
τ
′′
′
′
=
¡
=
where we are making an assumption that the massperunitlength of the string does not
change significantly. Thus, with
′
=1.2
, we have
/ 440
1.2 ,
f
′
=
which
gives
482 Hz
f
′ =
.
(b) In this case, neither tension nor massperunitlength change, so the wave speed
v
is
unchanged. Hence, using Eq. 17–38 with
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This note was uploaded on 03/20/2010 for the course PHYSICS 191262 taught by Professor Najafzadeh during the Spring '09 term at The Petroleum Institute.
 Spring '09
 NAJAFZADEH
 mechanics, Mass

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