ch17-p112 - 112. (a) We proceed by dividing the (velocity)...

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/ / ff λτ μ τ ′′ = ¡ = where we are making an assumption that the mass-per-unit-length of the string does not change significantly. Thus, with =1.2 , we have / 440 1.2 , f = which gives 482 Hz f ′ = . (b) In this case, neither tension nor mass-per-unit-length change, so the wave speed v is unchanged. Hence, using Eq. 17–38 with
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This note was uploaded on 03/20/2010 for the course PHYSICS 191262 taught by Professor Najafzadeh during the Spring '09 term at The Petroleum Institute.

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