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Unformatted text preview: Page 1 Assignment 11 100 points Section 19.1 Problem 2 : (a) Positive; (b) Negative; (c) Zero; (d) Zero; (e) Zero. Problem 12 : the rectangle lies in the plane ? + 2 ? = 2 . So 2 + is a normal vector and 1 5 (2 + ) is a unit normal vector. Since this point is in both positive xdirection and the positive zdirection, it is an orientation for this surface. Since the area of the rectangle is 5 , we have = 2 + and ? = 2 + 3 ? + 5 2 + = 9 . Problem 24 : ?? = = cos = 6 = 6 4 2 2 = 96 Section 19.2 Problem 2 : ? + ? = ? + ? ( 3 + ? + ) ? 1 2 = 3 ? + ? 1 2 = 1 Problem 12 : = ? + ? + ? = ? + ? + (1 ? ) ( ? ?...
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 Fall '08
 FORTMANN

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