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Unformatted text preview: [0.160, 0.180], i.e., at t = 0.170. By periodicity, the first peak to the left of the origin (t=0) occurs at t=-0.010. Thus the initial phase of the sinusoid corresponds to 0.010/0.180 = 1/18 of a cycle, i.e., q = (1/18)*2*pi = 0.3491 rad which lies in the required range. (iii) At t=0, A*cos(q) = 2.5, therefore A = 2.5/cos(0.3491) = 2.6604 (iv) t = (0 : 1/150 : 2-(1/150))*0.180 x = 2.6604*cos(100*pi*t/9 + pi/9) plot(t,x) p...
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This note was uploaded on 03/21/2010 for the course ENEE 241 taught by Professor Staff during the Spring '08 term at Maryland.
- Spring '08