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Unformatted text preview: Therefore Ts = k*T/3 = k*(7/30) sec (k=1,2,. ..) (iii) Setting w = pi/7 = 2*pi*(Ts/T), we obtain Ts = T/14 = 0.05 sec and more generally, Ts = 0.05 + k*(0.7) sec (k=0,1,2,. ..) (iv) cos((16*pi/21)*n - phi) = cos((-16*pi/21)*n + phi). Using the negative value for w = 2*pi*(Ts/T), we obtain Ts = -(8/21)*T = -8/30 sec Then the positive values of Ts that produce the given x[n] are Ts = (0.7 - 8/30) + k*(0.7) = 13/30 + k*(0.7) sec...
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This note was uploaded on 03/21/2010 for the course ENEE 241 taught by Professor Staff during the Spring '08 term at Maryland.
- Spring '08