Unformatted text preview: Therefore Ts = k*T/3 = k*(7/30) sec (k=1,2,. ..) (iii) Setting w = pi/7 = 2*pi*(Ts/T), we obtain Ts = T/14 = 0.05 sec and more generally, Ts = 0.05 + k*(0.7) sec (k=0,1,2,. ..) (iv) cos((16*pi/21)*n  phi) = cos((16*pi/21)*n + phi). Using the negative value for w = 2*pi*(Ts/T), we obtain Ts = (8/21)*T = 8/30 sec Then the positive values of Ts that produce the given x[n] are Ts = (0.7  8/30) + k*(0.7) = 13/30 + k*(0.7) sec...
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 Spring '08
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 Periodic function, TS

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