hwsolB11 - x2 x3 x4b...

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Sheet1 Page 1 HW 11 Solution ______________ Forward elimination: m x1 x2 x3 x4b ___________________________________________ 210-1-2 -2401-23 -1/21-3/263/235 -3697-323 m x1 x2 x3 x4b ___________________________________________ 210-1-2 0-2107 -10-26236 3067029 m x1 x2 x3 x4b ___________________________________________ 210-1-2 0-2107 005229 -20010050 m x1 x2 x3 x4b ___________________________________________ 210-1-2 0-2107 005229 000-4-8 U can be identified now, U = 2 1 0 -1 0 -2 1 0 0 0 5 2 0 0 0 -4 L = 1000 2100 1/2110 3-321 The backward elimination: m x1
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Unformatted text preview: x2 x3 x4b ___________________________________________ Sheet1 Page 2-1/4 2 1 0 -1 -2 0 0 -2 1 0 7 1/2 0 0 5 2 29 0 0 0 -4 -8 m x1 x2 x3 x4b ___________________________________________ 0 2 1 0 0 0 -1/5 0 -2 1 0 7 0 0 5 0 25 0 0 0 -4 -8 m x1 x2 x3 x4b ___________________________________________ 1/2 2 1 0 0 0 0 -2 1 0 2 0 0 5 0 25 0 0 0 -4 -8 m x1 x2 x3 x4b ___________________________________________ 2 0 0 0 1 0 -2 1 0 2 0 0 5 0 25 0 0 0 -4 -8 normalizing the diagonals we get x = [ 1/2, -1, 5, 2 ].'...
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hwsolB11 - x2 x3 x4b...

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