hwsolB13

# hwsolB13 - HW 13 Solution _ Matrix A _ p m x1 x2 x3 x4 _ *...

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Sheet1 Page 1 HW 13 Solution ______________ Matrix A ________ p m x1 x2 x3 x4 ____________________________________________ * 1* 1 1 1 -1 1 -1 1 -1 -1 1 2 4 8 -1 1 -3 6 -9 ____________________________________________ * 1 1 1 1 * 0 -2* 0 -2 1/2 0 1 3 7 -2 0 -4 5 -10 ____________________________________________ * 1 1 1 1 * 0 -2 0 -2 * 0 0 3* 6 -5/3 0 0 5 -6 ____________________________________________ * 1 1 1 1 * 0 -2 0 -2 * 0 0 3 6 0 0 0 -16 ____________________________________________ The matrix is nonsingular. Matrix B ________ p m x1 x2 x3 x4 ____________________________________________ * 1* 2 3 4 -2 2 4 7 8 -3 3 5 9 12 -5 5 7 12 20 ____________________________________________ * 1 2 3 4 0 0 1 0 0 -1 0 0 0 -3 -3 0 ____________________________________________ Now, we do a permutation by interchanging rows 2 and 3. The corresponding P matrix becomes P = [ 1 0 0 0 0 0 1 0

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Sheet1 Page 2 0 1 0 0 0 0 0 1 ] This gives ____________________________________________ * 1 2 3 4 * 0 -1* 0 0 * 0 0 1 0 -3 0 -3 -3 0 ____________________________________________ * 1
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## This note was uploaded on 03/21/2010 for the course ENEE 241 taught by Professor Staff during the Spring '08 term at Maryland.

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hwsolB13 - HW 13 Solution _ Matrix A _ p m x1 x2 x3 x4 _ *...

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