Unformatted text preview: [A] 2 x 0.080 [0.20] x Rate4 [B] 4 y 0.040 [0.40] y =   = 4 = 2 x x = 2  =  =  =  2 = 2 y y=1 Rate1 [A] 1 x 0.020 [0.10] x Rate1 [B] 1 y 0.020 [0.20] y For C: Rate 3 [C] 3 z 0.160 [0.20] z =   =  2 = 2 z z = 1 Rate Law: Rate = k[A] 2 [B][C] Rate2 [C] 2 z 0.080 [0.10] z This reaction is 2nd order in A, 1st order in B, 1st order in C, and 4th order overall k = Rate/[A] 2 [B][C] For trial 1: 0.020/(0.10) 2 (0.20)(0.10) = 100 The same value will be obtained for all of the other trials....
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 Spring '08
 Martin
 Reaction, Ratio, Rate equation

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