mth536_problem_7_1a

Then by denition 7 7 3 it follows that 7 7

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Unformatted text preview: ondition 2 , and $ 1 § 9 1 7© $ 1 9 ¦ 1   & § © 7 7  ¦" & @  © ¦ 7 & § ©   7 " " ¡ ¢ ¦ © & & 87¤ 3 Suppose . Then by definition, ¤7   § 7 © ¤ 3 It follows that ¤£ ¨  © ¤7  § © & 7 © ¤7    @  ¡ ¢ and ¤ ¥£  ¡ ¦ § ¨ ¤£ Now suppose . Since is a sum of nonnegative terms, it can only be zero if each term is zero, in which case for all and by definition . ¡ ¢ ¦ § ¤ © § 7© § ¤7 $ ¨ ¦& – p. 5/ Proof that 4 and § ©  satisfy condition 2 , and $ 1 § 9 1 7© $ 1 9 ¦ 1   & § © 7 7  ¦" & @  © ¦ 7 & § ©   7 " " ¡ ¢ ¦ © & & 87¤ 3 Suppose . Then by definition, ¤7   § 7 © ¤ 3 It follows that ¤£ ¨  © ¤7  § © & 7 © ¤7    @  ¡ ¢ and ¤ ¥£  ¡ ¦ § ¨...
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This note was uploaded on 03/23/2010 for the course MATH 515 taught by Professor Staff during the Spring '08 term at Iowa State.

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