HW2_20 - 1+ ] = 5.37 log [H 1+ ] = -5.37 [H 1+ ] = 10-5.37...

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Homework due 2/20 Calculate the [H 1+ ] and [OH 1- ] of a solution of pOH = 8.63. pOH = - log [OH 1- ] = 8.63 log [OH 1- ] = -8.63 [OH 1- ] = 10 -8.63 = 2.3x10 -9 pH = 14 - pOH = 14 - 8.63 = 5.37 pH = - log [H
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Unformatted text preview: 1+ ] = 5.37 log [H 1+ ] = -5.37 [H 1+ ] = 10-5.37 = 4.3x10-6 Alternatively, [H 1+ ] = 1.0x10-14 / [OH 1-] [H 1+ ] = 1.0x10-14 / 2.3x10-9 [H 1+ ] = 4.3x10-6...
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