krueger (mck734) – HW #4 – lewis – (21514)
1
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printout
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have
38
questions.
Multiplechoice questions may continue on
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before answering.
Chapter
19
......
if
you
forgot
how
to
solve 3 equations for 3 unknowns,
review
http://en.wikipedia.org/wiki/System
o
f
l
inear
e
quationsSolving
al
inear
s
ystem
001
(part 1 of 2) 10.0 points
A battery with an emf of 12
.
9 V and internal
resistance of 0
.
96 Ω is connected across a load
resistor
R
.
If the current in the circuit is 2
.
02 A, what
is the value of
R
?
Answer in units of Ω.
002
(part 2 of 2) 10.0 points
What power is dissipated in the internal re
sistance of the battery?
Answer in units of W.
003
(part 1 of 4) 10.0 points
A battery has an emf of 12 V and an in
ternal resistance of 0
.
2 Ω.
Its terminals are
connected to a load resistance of 1 Ω.
Find the current in the circuit.
Answer in units of A.
004
(part 2 of 4) 10.0 points
Calculate the terminal voltage of the battery.
Answer in units of V.
005
(part 3 of 4) 10.0 points
Find the power dissipated in the load resistor.
Answer in units of W.
006
(part 4 of 4) 10.0 points
Find the power dissipated in the battery.
Answer in units of W.
007
(part 1 of 5) 10.0 points
A string of 23 identical Christmas tree lights
are connected in series to a 120 V source. The
string dissipates 55 W.
What is the equivalent resistance of the
light string?
Answer in units of Ω.
008
(part 2 of 5) 10.0 points
What is the resistance of a single light?
Answer in units of Ω.
009
(part 3 of 5) 10.0 points
How much power is dissipated in a single
light?
Answer in units of W.
010
(part 4 of 5) 10.0 points
One of the bulbs quits burning.
The string
has a wire that shorts out the bulb filament
when it quits burning, dropping the resistance
of that bulb to zero. All the rest of the bulbs
remain burning.
What is the resistance of the light string
now?
Answer in units of Ω.
011
(part 5 of 5) 10.0 points
How much power is dissipated by the string
now?
Answer in units of W.
012
(part 1 of 2) 10.0 points
Consider the following two cases.
4 A
E
2 Ω
2 Ω
Case
a
4 A
E
2 Ω
2 Ω
Case
b
Find the ratio of dissipated powers,
P
a
P
b
.
1.
P
1
P
b
= 8
2.
P
1
P
b
=
1
8
3.
P
1
P
b
= 4
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 Spring '10
 Jarafee
 Physics, Resistance, Light, The Circuit, Electrical impedance, Krueger, Voltage drop

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