Physics9C_A_MT2

Physics9C_A_MT2 - 1 = R 2 = R 3 = R 4 = 6 Ω and ε = 72 V...

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Physics 9C-A Midterm Exam #2 Winter 2010 1. In the following circuit, C 1 = C 2 = C 3 = C 4 = 8 µ F, and V ab = V a – V b = 20 V. (a) (8 points) Find the equivalent capacitance between a and b ; (b) (8 points) Find the charge on each capacitor; (c) (4 points) Find the potential difference across each capacitor. 2. A slab of dielectric material with κ = 6 , thickness a and area (2/3)A is inserted between the plates of an air parallel-plate capacitor with plate area A and plate separation d . Here d a . (a) (10 points) Find the capacitance C of the capacitor in this arrangement in terms of the capacitance C 0 when the dielectric slab is removed; (b) (5 points) Find the capacitance C in terms of C 0 when a = 0; (c) (5 points) Find the capacitance C in terms of C 0 when a = d . 3. In the following direct-current circuit, R
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Unformatted text preview: 1 = R 2 = R 3 = R 4 = 6 Ω , and ε = 72 V with negligible internal resistance. (a) (10 points) find the power dissipated in R 1 and R 2 ; (b) (10 points) Now remove R 4 from the circuit, and find the current through each of the remaining three resistors. 4. In the following direct-current circuit, (a) (8 points) Find the magnitude and direction of the current in the circuit; (b) (6 points) Find the terminal voltage of the 4V battery, V bc = V b – V c ; (c) (6 points) Find the potential difference V ad = V a – V d . 5. In the following direct-current circuit, (a) (10 points) Find the current (direction and magnitude) in each branch; (b) (10 points) Find the potential difference V ab = V a – V b ....
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This note was uploaded on 03/23/2010 for the course PHY 009c taught by Professor Zhu during the Spring '10 term at UC Davis.

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Physics9C_A_MT2 - 1 = R 2 = R 3 = R 4 = 6 Ω and ε = 72 V...

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