This preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: 1 = R 2 = R 3 = R 4 = 6 Ω , and ε = 72 V with negligible internal resistance. (a) (10 points) find the power dissipated in R 1 and R 2 ; (b) (10 points) Now remove R 4 from the circuit, and find the current through each of the remaining three resistors. 4. In the following directcurrent circuit, (a) (8 points) Find the magnitude and direction of the current in the circuit; (b) (6 points) Find the terminal voltage of the 4V battery, V bc = V b – V c ; (c) (6 points) Find the potential difference V ad = V a – V d . 5. In the following directcurrent circuit, (a) (10 points) Find the current (direction and magnitude) in each branch; (b) (10 points) Find the potential difference V ab = V a – V b ....
View
Full
Document
This note was uploaded on 03/23/2010 for the course PHY 009c taught by Professor Zhu during the Spring '10 term at UC Davis.
 Spring '10
 Zhu
 Physics, Capacitance, Charge

Click to edit the document details