solution_hw2[0] - 3.11 7 y' max 3 55o x x (a) x = 30 - 70 2...

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3.11 7 3 y x x τ max 55 o (a) σ x o =+ −+ 30 70 2 30 70 2 25 5 cos ( ) = − = − 20 171 371 .. kPa y kPa =− + = − 20 171 29 xy o kPa = + 30 70 2 5 4 7 sin ( ) ( b ) max [() ] −= 1 2 30 70 50 kPa 3.23 Refer 2 nd column of C, Table 3.2. EEE G P a r m m r m mF k N m 12 1 2 1 210 7 45 200 === = = = Hence ∆= = = = = 22 210 1 105 1 0007 1 0045 99 120 635 E n (10 ) (10 ) ,. ( a )
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This note was uploaded on 03/24/2010 for the course ME 031 taught by Professor Kim during the Winter '10 term at Korea Advanced Institute of Science and Technology.

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