KEY EXAM 2 F2008 - Last Name First Name Lab Sec. # ; TA: ;...

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Unformatted text preview: Last Name First Name Lab Sec. # ; TA: ; Lab day/time: Andreas Toupadakis, Ph.D. Fall 2008 CHEMISTRY 2A Section D Good luck © EXAM 2 Multiple Choice (circle one) Insfrucflons: CLOSED BOOK EXAM! No books, notes, or additional scrap paper are permitted. All information required is contained on the exam. Place all work in the space provided. If you require additional space, use the back of the exam. A scientific calculator may be used (if it is a programmable calculator, its memory must be cleared before the exam). This exam has 10 pages. (1) Read each question carefully. (2) For Parts I and II, there is no partial credit given and gn_|y answers marked on this cover page will be graded. (3) The last 2 pages contain a periodic table and some USeful information. You may remove them for easy access. (4) If you finish early, RECHECK YOUR ANSWERS! 1-9 total points: U.C. Davis is an Honor Institution 10. A 8 @ D E Z 3 4 5 6. 7 8 9 Possible Points Points # 1—9 (4 points each) / 36 # 10—15 (6 points each) / 36 # 16 (16 points) / 16 # 17 (8 points) / O8 # 18 (4 Poims) / 04 10-15 fofa/ poi/ifs: Total Score (100) / 100‘, Toupadakis 2A Fall 2008 EXAM 2 (Page 2 of 10) Part I: Multiple Choice, Concepts (4 points each) Select the best answer and enter your choice on the cover sheet - No partial credit 1) Which of the following combinations of reactants will yield a precipitate? ©AT2008FALL A. H2504(aq) + NH3_:(aq)_ 3- Pb(N,03)2(d<i) C. HCl(aq) + NaOH(aq) ——> D. HCl(aq) + Zn(s) -—> E. KCl(aq) + NaNO3(aq) ——> 2) Which of the following incomplete chemical equations leads to: ©AT2008FALL H*(aq) + OH'(aq) —-—> HZO(|) as its net ionic equation? A HZSO4(aq) + NH3(aq) ——> B. Pb(N:O3)g(aq) f _KI_( c. Hamel.” 7 q _ D E HCl(aq) + Zn(s) —-> KCl(aq) + NaN03(aq) —-—> 3) Oxidation is: ©AT2008FALL A. gain of oxygen 8. loss of hydrogen C. loss of electrons D. electron depletion E. all of the‘above 4) Which of the following mathematical expressions states Avogadro's law? ©AT2008FALL A. V_= kn B. V = k/P C. v : kT D. met : ZV. E. Rate = k/M“2 Toupadakis 2A Fall 2008 EXAM 2 (Page 3 of 10) 5) The volume of a gas was increased by six Times, iTs absoluTe TemperaTure was Tripled and The number of HS molecules was doubled. ITs pressure: ©AT2008FALL A. increased B. decreased C. sTayedlkThe same D. was doubled E. was Tripled 6) Which of The following aTomic models relaTes To The sTaTemenT ThaT The posiTive charge of The aTom is spread all over The volume of The aTom? ©AT2008FALL A. PlumyPuddiné m B. Nuclear Model (RuTherford Model). C. Solar SysTem Model (Bohr Model). D. The orbiTal Model (Heisenberg—De Broglie — Schrodinger Model). E. none of The above. 7) More negaTive energy of an elecTron means: ©AT2008FALL The elecTron is furTher away from The nucleus weaker aTTracTion beTween The elecTron and The nucleus The energy of The aTom is higher The aTom is less sTable none of Thtteabov'e (“3090.) 8) The fourTh quanTum number of an elecTron relaTes To The: ©AT2008FALL size of The orbiTal iT resides shape of The orbiTal iT resides orienTaTion in space of The orbiTal iT resides ,ro’rqfiénql 'mOTion none of The above mvow> 9) Two doTs are aT a disTance of 3.8 nm. The radiaTion we will have To use in order To be able To see The Two doTs clearly musT have a wavelengTh of: ©AT2008FALL A. 2.5 nm B. 3.8 nm C. 3.9 nm D. 4.2 nm E. 5.0 nm Toupadakis 2A Fall 2008 EXAM 2 (Page 4 of 10) Part II: Multiple Choices, Short Calculations (6 points each) Select the best answer and enter your choice on the cover sheet — No partial credit 10. 11. Consider a mixture of sodium carbonate NazCO3 and Sodium hydrogen carbonate NaHCO3. Its mass is 45.0 g. The mixture is reacted with excess HNO3 solution and the produced C02 gas occupies 10.0 L volume at 85 °C and 1.32 atm. What is the Ncho3 "/0 by mass in the above mixture? ©AT2008FALL A' 6700/" x06 N01C03 t’l/l./U.<NC11CO‘5) : l06.0 (j /UA0’€ B. 49.0% , - . . “2.0% x) 3 WuHco—g MM. (NoiMOz): 8am B/WOK {158.0% X’rj:L1S.Oa 'Tlcagt 7.1% ZESBR E. 13.0% Mo€~€5 (0:1 pYoduCfld (+0153) : pV : aqua vvxo-g COL QT NuxCOB + ’lHNOB "—5 )Non NO; t (02 t HLO (X/i0603 were (x/‘Oehcfl “My? NQH(03 ‘l' RN03 “‘9 NGNOZ \- COZ + H10 (9/9110!) WK (y/euoi) wwé We,“ SOOWZO'20. LiLi°l )b-€CWS€ xztisicrj —s \l = xtoO A 1.58 9 sample of a diprotic base is dissolved in water, and the resulting solution is titrated with 0.0100 M HCI solution. A 60.5 mL volume of the acid solution is required to neutralize the base solution. Calculate the molar mass of the base. ©AT2008FALL A. 5.21x1o3ag/mol 3- 121x1049/m0' Coo-s wanKomoo/unozl «—. ocos WWI me C. 8.21x105g/mol E. 7.21x109/mol '— (obos mam-Jena) (ban /\A(OH ) L lynx/Wore HQ :203 x \O’L‘ \mo’e MCOML. . /" «g - W ————V“ v "€63 w: MM. (-43 MN" m -30'3Y10'4'Wo? 3/”,.€ Note: ’Flwe loose Cooéol, be, u/éovoe, evoumi‘c vvwéacu/KQ ./6l K6 LNRL\ --,_ ) B 1’ «go/“6% Cux/bov /H Puv‘b Name 12. 13. Choose The correcT sTaTemenT. A. B C. D. E . None of Thefaboye Fall 2008 EXAM 2 (Page 5 of 10) ©AT2008FALL The mean speed of a hydrogen molecule aT 300K is The mean square speed of an ozone molecule aT 300K is The rooT mean square speed of an oxygen aTom aT 300K is The y’mosT probable speed of a meThane molecule aT 300K is WhaT is The pressure of 50.00 mol of niTrogen aT 285 K in a 30.0 L conTainer using The van der Waals equaTion? If you use The ideal gas equaTion will The pressure be The some, larger or smaller? For niTrogen The van der Waals consTanTs are; a = 1.39 L2 aTm/mol2 and b = 0.0391 L/mol. ©AT2008FALL A B. C. D E ‘ 37.9: aTm, L'la‘rge‘r . 56.9 aTm, smaller . 19.1 aTm, some 9-: 45.3 aTm, larger 25.5 aTm, larger 'Tl/H’Nf’fore 1 .1 A 1 _ (€0.00 We) (neiuomwz 7’) l l C%0.0Lll goooxooelixzeg __ 33.86 OR“ > 20.0 —- 1.056 _/ Name Fall 2008 EXAM 2 (Page 6 of 10) 14. According To Bohr‘s Theory, The ionizaTion energy of The He+ caTion is: ©AT2008FALL A. RH Joules . ZRH Joules 1 ,1 .4RuJ0ules BE: QR( Z — 1 B C D. 7RH Joules W57, hi1, E. 9RH Joules 'Z'Zr’l \fl; :1 W{ 1 ob ) s ‘Tl/i €Vf/TEOY62 7. ’1, - . DEZQH “(1 v—L 3Q <"\"0> i1 1 H DC) 06: M2“ 15. How many unpaired elecTrons are in The ground sTaTe elecTron configuraTion of Fe3’? ©AT2008FALL W6 lnowe Vfi l:qu Hclzdé CV 96, CA8 156 MC 7’ lay VWov.vv> Q.) 638' C ®®®®® 2 d Name Fall 2008 EXAM 2 (Page 7 of 10) ParT III: ParTial CrediT May Be Given (28 poinTs) Please show all work for calculaTions 16. (16 poinTs) Balance The following chemical equaTion by The half-reacTion meThod (show your work), and nexT answer The following quesTions. ©AT2008FALL 6 F§(CN)63’ + Cr203 + 10 OH' ——> 6 Fe(CN)64' + 2 Cr042‘ + 5 H20 i, *3 +2 +6 39+ we GXL FeCcrx/lc3 +ie’ ———> FfiCCNlGH’] *6 1)) Pi I—anzoa + SH’LO "éflCYOL‘l‘ Jr MDT-“+6 6' +77 OX ~ g 2 “ w L\ _ +1 lveo- 29+”? Gl:t (CNN, «9/, e —9 éFe CCle Cvzogs T gixlo ——-> 1am,” + low ice’ 0 "”) : * I?) w _ q', 1’, a? A M We? 6 Fe C C Nlc + CY’LOX T 54416 ——> 6€cCc Me +2CYOH + ie/R / + (O OH- (($969- pzfilu‘) // a. The oxidizing chemical species is: Per C C N‘ 6 3 S l b. The reducing chemical species is: CY '2. O '3 \ c. The name of The oxidized elemenT is: C l/‘\ Y0 WT UW‘ ) d. The name of The reduced elemenT is: \ VOW I e. The oxidanT is: C6 CCN\6 3‘ x," i f The reducTanT is: (VI 0 ‘3 I ‘60 C h g The name of The elemenT ThaT gains elecTrons is: \ VOW § h The name of The elemenT ThaT looses elecTrons is: CV‘ YO Wyl‘vw‘ l i. The chemical species ThaT cau5es oxidaTion is: g 6 CC N l (5 a v j. The chemical species ThaT causes reducTion is: CY 2,0 3 s] k. The oxidaTion number of C Y (give The chemical symbol of The elemenT) é increases from i To l. The oxidaTion number of Fe (give The chemical symbol of The elemenT) decreases from i To 1’} Name Fall 2008 EXAM 2 (Page 8 of 10) 17. (8 points) ©AT2008FALL Consider an electron and a fly moving along the x axis. If the uncertainties of their speed are the same, Au(electron) = Au(fly), the uncertainty of the fly‘s position is 10'30 m and its mass is 1.00 9, then what is the uncertainty of the electron's position? But : 13ozi 13x4 : I073°W 3 WV; 2 L003 } DXez’f? ) DXe: \A : l/l - “:20; MTV \Me Due Ll'Ti Wm; but: dividiwa ‘hViOS‘e {qualiom§; DXC _ Ni AXi We OY DXe: W16 th We 0 "T . . 7 0 ‘~ Me : (\0 ‘ml< “3/3 we > 0),io<528?v to “(3f Q- o Jr. 18. (4 points) (show your work) Use the following three equations to derive de Broglie’s equation, A = h/(mu). ©AT2008FALL E = hv c = v A E = mc2 4L Pt l Pl E \A ‘ 1 V :‘V/y‘z-x—a ">\:C a): C/l Mg} V . m 1 E. 6 A la l/\ ' E : \M C L g/ «3 1 - _ _.____.> 3 _ , g t (l p+ mm C 2: Name Fall 2008 EXAM 2 (Page 9 of 10) Potentially Useful Information: (You may remove this page for ease of access) Solubility rules: Soluble or mostly soluble compounds: - Group 1, NH4*, chlorates, acetates, nitrates - Halides (except Pb”, Ag*, and H92”) 0 Sulfates (except Sr”, 802*, Pb”, and H92”) Compounds that are I'nso/ub/e o Hydroxides, sulfides (eXCept above rule, and sulfides of group 2) - Carbonates, phosphates, chromates (except above rules) Some useful equations and data: PLEASE NOTE: Important values and equations required for calculations are given with the respective problem. The following may or may not be of any use. 1120 P + —— V — HI) = nRT P = ghd PA = X, PW, [ V2 y ) Rafe/Rafe] : (MI/M2) 1/2 22 Pl/rnRT E,,=—RH—2 9:8.314Jmo/"K" JJ:Jkgm25'2-'1Nm n mL-M : mmo/ mom/.- PJ + P2 + TK : m 273 R : 0.082] L arm Ina/'1 K'J 77:3.14 Ax-Ap:h/4n NA :6.022X1023 c=3.00x103ms '1 P; X,: "A P_1V.1=PZV2 Mia A "mm! an1 ’7sz P V k M 1 PM n (moles) = w— /l = — Molarily = 0 es d = —— molar mass (g/mol) mu Volume RT c=V/l AE=hv Ephmn=hv Ap=mAu 2 2 um = 3131 M = RH [z—z —Z—2] 1 pm : 10-12 m m - 9109387240 '289 M n]. n], my”; Inm:10'9m RH:2.J79XJO'JBJ h=6.626x10‘34Js Name Fall 2008 EXAM 2 (Page 10 of 10) PERIODIC TABLE Potentially Useful Information: (You may remove this page for ease of access) Key Atomic Number 2 Symbol He Atomic MOSS 4003 Electronegativity _ 9 B C N O F Ne 10.81 12.01 14.01 16.00 19.00 20.18 2.04 2.55 3.04 3.44 3.98 — 13 14 15 16 17 18 AI 5i P 5 Cl Ar 26.98 28.09 30.97 32.06 35.45 39.95 1.61 1.90 2.19 2.58 3.16 — 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 Ti V Cr Mn Fe Co Ni Cu Zn Ga 6e As Se Br Kr 47.90 50.94 52.00 54.94 55,85 58.93 58.70 63.55 65.38 69.72 72.59 74.92 78.96 79.90 83.80 1.54 1.63 1.66 1.55 1,83 1.88 1.91 1.90 1.65 1.81 2.01 2.18 2,55 2.96 - 4O 42 43 47 53 Zr Nb Mo Tc Ru Rh Pd Ag Cd In 5n 5b Te I Xe 91.22 92.91 95.94 (98) 101.1 102.9 106.4 107.9 112.4 114.8 118.7 121.8 127.6 126.9 131.3 1.33 1.6 2.16 1.9 2.2 2.28 2.20 1.93 1.69 1.78 1.96 2.05 2.1 2.66 - 72 76 83 85 Hf Ta W Re Os Ir Pt Au Hg Tl Pb Bi Po At Rn 178,5 180.9 183.9 186.2 190.2 192.2 195.1 197.0 200.6 204.4 207.2 209.0 (209) (210) (222) 1.3 1.5 2.36 1.9 2.2 2.20 2.28 2.54 2.00 2.04 2.33 2.02 2.0 2.2 - 104 105 106 107 109 Unq Unp Unh Uns Une 58 59 6o 61 62 63 64 65 66 67 68 69 70 Ce Pr Nd Pm Sm Eu Gd Tb Dy Ho Er Tm Yb 140.1 140.9 144.2 (145) 150.4 152.0 157.3 158.9 162.5 164.9 167.3 168.9 173.0 1.12 1.13 1.14 1.13 1.17 1.2 1.20 1.2 1.22 1.23 1.24 1.25 1.1 90 91 92 93 94 95 96 97 98 99 100 Th Pa U Np Pu Am Cm Bk Cf Es Fm 2320 (231) 238.0 (237) (244) (243) (247) (247) (251) (252) (257)( 1.3 1.5 1.38 1.36 1.28 1.3 1.3 1.3 1.3 1,3 1.3 101 102 Md No 258) (259) 1.3 1.3 ...
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KEY EXAM 2 F2008 - Last Name First Name Lab Sec. # ; TA: ;...

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