{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

ex7_11 - q = 10 N = 21 omo = 9.5*pi/21 n = 0:N-1 x=...

Info icon This preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
% Example 7.11 q=10; N = 2*q+1; omo=10*pi/21; n=0:N-1; x=cos(omo*n); Xk=dft(x); k=0:N-1; clf subplot(311),stem(k,abs(Xk)) title('Example 7.11, q = 10, N = 21, Omega = 10pi/21') ylabel('|Xk|') xlabel('k') text(6,10.5,'10.5') text(17,10.5,'10.5') % % redo with a different N and Omega
Image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: q = 10; N = 21; omo = 9.5*pi/21; n = 0:N-1; x= cos(omo*n); Xk=dft(x); k=n; subplot(313),stem(k,abs(Xk)); title('Example 7.11, q = 10, N = 21, Omega = 9.5pi/21') ylabel('|Xk|') xlabel('k') text(6,9.5,'9.81') text(17,9.5,'9.81') subplot(111)...
View Full Document

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern