Homework 1 - 6"" ffi,x L° 2.3 C “:5“ J...

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Unformatted text preview: . ._ 6"" ffi: ,x L°\ 2.3:: +C “:5“ J miller (dkm645) w HWOE. ~- hamrick — (57395) i / r?“ I f! This print—out should have 20 questions. Multiple~choice questions may continue on 003 10.0 points the next column or page — find all choices before answering. Determine if 001 10.0 points lim tan‘1 5 + 43: 56 a 00 4 ~+~ 2:122 Det m’ne if er 1 exists, and if it does, find its value. 1' {1 7 3 —1 1 7 } - \ $3513... M + m) M + :6) 1.1mm; 3% W (399) exists, and if it does find its value. @“ it m 0 1. limit 2 In 7’ MW 3325 1 7‘ ”A: 60 \‘A’ H’ 7V“ 3. limit does not exist 7 j” is» ma 7 4. limit m '6 " 1 . . 3. limit : In — . . 1r . 7 5. limit 2 — 2 .. ; . 3 - @111: Z in *7 6. limit 2 35 4 5. limit does not ex1st 00 4 10.0 points . . Express the function 002 100130111133 git)"; . 2 2 mg ’0’ flan) = 3m mfficos 3; Determine if in terms OfCOS 251;. 5m) y “ELQFK 3f? .. .. flfihymgffn—Cm ix} lim siQJ 3+ .. : @m) = —-2—— 300823: 2” E ' aim—>00 if: I 5 p S P. “Q; ‘2 I. 2. f (:3) m —3+2cos2m infa3‘“? " .— 3306"“ exists and if it does, find its value. / ' _ Q -" Lo m?» z“? . ‘ . 3 fix) : m2+30082m "L ' i' 1. 11m1t does not 6x131; W .4 {2% > 3 ‘ "We” *2, 4. ill?) W 3—2005293 W 2-" 9*~“’“~"" 7r 2. 1' 't = w 1m: 2 5 fix) 2 2m36082m , _ 7r 3. limit m 3: 6. f(a:) m 3+20082m 4. limit 2 0 005 10.0 points Determine if the limit 5. limit = . 11m mW—OO ii wl=¥ mi: i I exists, and if it does, find its value. mifier (dkm645) w HWOI w hamrick w (57395) 2 . . 2 , 23in(1n 2:17) 1. 1111111; 2 g 5 f (m) m “T“ Omit 2 —§ 6 f’(m) 2'2 — sin(1n2:1:) 3. limit = "E 008 10.0 points 2 3 Determine the value of f’”(1) when \‘i 4. limit 2" — 2 [(m) m 3111(a:+ 1). r :1 $ 5. limit does not exist 3 “P ( x 3 1" ffll(1) : mm 006 10.0 points 3 m __ MW Find the value of f’(—1) when 2‘ f (I) " 2 f($) : 3:3 4“ 43:2? Wax 3 fm(1) : g .9134) 5 gvd - 3Q» ‘FIC ”Q” ‘1'- "a ,4. 2' m __ 3 f 1 f’(——1) 2 3 4» 4:32 Ym’ 4‘ f (1) "" Mg 500 ‘" '5 m 3 (14M F9 M" 5 f (1) = »— 2 f’(“1)m“3+432 2 o eulb’wl/ 3 T“ 3 f’(—1) m —3 ~ 832 g (23 H) 009 10.0 ' t 4. f’(--1)—w 3 — 863 9011131“ Differentiate the function yw w 9 a: W“? O(’"1))m3— 8'32 y,m9+m—m1n;c t, LjékLflHJNKJ .4 ._ (9 + ac)2 ’V ‘ fur/R 007‘ 100130111128 .y’=9+$+m1n$ {21476 “vine Difierentiate the function :E (9 + at)2 X, c: m 1 z 3 fan 2 (305111232) r 3. ’_W ( ) m<§£fi ii}: Hf 3’: -7 “wir” y $(9 mi" in) HHHHH Z Y 9 ~§~ :10 a: In a: I 4.. I: g 7; I m ___.__. m LA (fl “f; ' ; /:- 1' f (3:) 903011 21:) Lqu—Ewm ' $(9 ~3— w)2 “‘4‘“ N . _ 9 5m 11123: -- 5,24; . I z 2. mm) : __L$__)_ W33 {,4 em L 4? y 2:2 (9 4 at) 4 V w of . 2 sin 11123: M mix-- 010 10 O pomts 3- f’(w) = ”WW—"mm; ) gay: 42.. ‘2} 4/ O W " Calculate fan 9) when 5111(1112az) X "f 1‘ 4 ”—7. (414543 3 m) m In («4+ em). m- '1 19 I r “a m_ \ I .x, If: “M , (j “ \,_ J -——»—--*~".“Q_l "4 N L if, r 2' W) 4 E” 4 ”Her (dkm645) — mm m hamrick w (57395) 3 ,4; “-5. ”a“ \J E! \ 011 10 points 013 10.0 points M VOA/LIX : I Find the derivative of 9 when S1mphfy the expresswn 440W, <52 H W gym): 2 sec 9: + tan 3:. ”1.7“ ft”) : COS (tan 131/ +0M:@;"/ {3/ .25m; WW r. «aw Se. a: La: W - 0”3i 2 - 1 f() 1 m2 A 1. g(m) ——. 2cosmsec 39—1—1 seen: . a: = —— Q ) I Hi -) : ZSecmtanx+sec2m . m m 2 V 1 + 332 3 f(:c) _ a: { 3. g’(a:) m 2secmtanac +1 — tan2 a: . W /;..- :1: KEV ; 5 4. '(x) = 28inmsec2 3: ~— 0052 ac 4 fix) ~ 9 ' 1 — m2 2cosxseczm+ 1 +tanrc 014 10.0 points £31 £41 A 5% V II M i >< U! \Q z-Z‘ 8 V El Find the derivative of f when 61% {9 ‘>: E 012 10 0 points 2% E» f (w) __ SiIIiB M 1 ‘T: " W K 1’ KFind the derivative of M”- ) ~ 3: wcosm' z’r- , h . \, ~ ~1 3% AC “f? .mwwmm)- g,» ——:flflm‘£€§ caé 2< . m _ 2 «as T76 {:2 3 MK fl " - (37 (30353) t K ‘K 38 03 (P K . : ‘ ‘IMI—L 2L [m D 1 m (—20 -~« 633 J)?“ 2. f’(:v) = W ' 5‘! 1+8 (armcosw) 3 :13 Sing; 2- f’(33) : 1+865t: 3' f’(:c) m —(33——cosm)3 1 .‘I: COSIL' I ___ W = W 3- f(93) “— W (m——cosr1:)2 miller (dkm645) w HW01 * hamrick ... (57395) 4 , _ :1: cosm 5' f(m) .- (1+Sinzn)2 015 10.0 points Find f’(~w1) for m) m 7(63+m2)1/2. F L: r' 016 10.0 points Find the second derivative of f whee}; _‘ wag: ' flat) 2 w3c082zl: 46' . _ _‘ -F i( F0 :. (c7 3%.“: V4-.-” ‘ . -1}: +2.2; V” 1. f"(m) 2 14501251: $“LKO "‘7 \“Lcm .9" L ‘k:() r , . 1L ' VA; 2. f"(:1:) m ~14cos32m 153(k): (pain-2x .r FHCK) 1: IZCD<ZK '11," ZCC’fi‘Zx 2. limit ”0" K . . w - 2 _. NIH-"EFL f < :19" M SJ 3. f"(a:) 2 —14 5:112:12 H CO say 331me (Va: - + 2 a2) {filing ’\ , V ‘ ~2- 4» 2:5 . . . . . “Cf“ “if 4_ f”(93) m ~7sin 23; Z- “?5 X ems-t and 1f1t does, find 0538.111; r '22. ' . 1.x 1“ . {ix/”134 1. mi. 3 0- f A? (P '(zc) m 14 cos 23: 3.23ng f «i 1’ wmgm £36 \JY‘EQ} '3, ”4”” 6. ”.73 m 70052.1: f ( ) 3. limit 2 1 017 10‘0 901mg 4. limit doesn’t exist - . If __ x13 Fmd the value of f ( 1) when 43.9 5_ limit : x/g _ f(:1:) = 3m7 +~ 3m4 + 9mm . _- . , y 5. ‘1” \2 K 5 4 ”if?“ - _ 020 10.0 pomts Y. x: 018 10.0 points Determine if the limit ‘1'“ V W ‘lfiewrite the finite sum 1‘ t a: ,. z n \ L , r lim — .— 33 {52.0 TI?” ‘E’J 1 {a “f g mwoo 4 38‘” + 2 ' w exists, and if it does, compute its value. 'h m v ”3.5 1 .a M— “1/ 1. limit : ‘4“ f/Lg i“ V} :«M L 2’ using summation notation. ‘ 1 _ V9 "5 2. Emit = WW “V4”:- 1. cf _ ~. 9 k 12 :9. m wi- g: T; 1_ Z W . ‘ 1 l“) W; 126:3 k+4 3. 11m1t ... _E miner (dkm645) w HWOl - hamrick m (57395) . limit does not exist 4 / f _ i' Z" r” ...
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