TA Practice Exam 2 - A} ow, {Mm CC < NH <...

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Unformatted text preview: A} ow, {Mm CC < NH < BO'< Lil: V\6\f\ 1‘5 5% 3 .BO<CC<LiF<NH c. E\§H<BO< LiF<CC d. CC<BO<NH<LiF ' 1';“Rank“the@iowmg in increasing bond polarity: CC; 30, NH, Li? 2. Which of the foliowing can be polar molecules: 1. coa X I Fe(c0)5 III. 03 v’ a. I ,, a u a. Octahedrai, 90, 120 4 Q b. Square Pyramidal, 90 c. Octahedral, 90 gql‘l‘w ' d. Square Pyramidal, 90, 120 xiii-QTSFWNm hybrid e 6. Determine the electronic geometry of ICiz'. a. Trigonel pyramidal b. Bent Teerahedrai Trigonaieipyramidai. . \ K c orbitals. are present in XeF4? dsp3‘ d25p3 I. WWW . d25p2 A ., :il‘jeterrfiine‘EHET’EEE e6rhé'firy’i'oflhebxygén ln CH3OH"; I " :g, letrahedtai . , -—. w T ofaod‘h'ibonqe are there'ihlftsz? _ ' V I l ‘ .. -'“4¢and111f1;- — . _ floand " c. 20 and 3:": d. 30 and in a 9. What atomic orbitals are used in the bonding of NO? --—-—-~ 3. 25 b. 23 arid 2p NO ’ ' LILIII " ' ‘ ' . <— em / \5 . g; c- , I, H C \ EN 69 “ O " '3. 'Whicfi'Of the folio'wing moiecuies is nonpolar? ‘ - /O - ' ' . NH3 \/ I l / l C - -- 304 2— x ‘ , A M, F” ‘r F, sozq/ <3 M” .WWO d. BFZCI , i .r K KW _- _ 4. Determine the moiecuiar geometry and bond angles of bromine peotafioride (BrFS) "I; (@213 . 15, 25, 2;) 10. Using molecular orbitai theory determine which of the following molecules can exist and no be paramagnetic. I —~~ Kw —~" 3. 52 as 4r @ et- 4{ 4!? 4 E 2347 Miranda, Question Types 11—20. 11. What is e elec onic gonfiguratéon of 132'? fin, } ow a. (025)2(025*)2(Tr2p 7 41/ ‘c. (02s) (025*)2iw2pl22 2 5&6? {13% d- (028) (02s*) (02p) (mp) ' ' WW 17 r - w» — Wig”? 12. What are the bond orders for N24“, N2, and N2? _._-- .. . a. 3.553; 3.5 1.5 3 LS Mag; 4,. - r- 24) an. . I 1 t3; V m it» t” at e ich molecuie is diamagnetlc? :H'; , Q - 2* ill, H; 4i 14. %ased on bond order, what is true about the difference between the bonds in Liz and C2? 5 ' " a. C2 has a Eonger bond length and a higher bond energy than L12. F“ C2 has a ionger bond length and a lower bond energy than Liz. 2 has a shorter bond length and a higher bond energy than Liz. rm" ‘1 C2 has a shorter bond length and a Eower bond energy than LE2. 22¢ Clix ‘ (3035 15. Which of the following species does not e’xgit resenance? . 2.0» , . . . . ‘ a. 503 . VAC]... @Pcl Corr , J, , 5 .e ./ - L ‘- \ - - c. mow. teed? 0/ “N3, .3. c H ‘ so ‘ . u ' 6 6V I 16. At constant temperature and pressure, the voiume of a gas wiil increase as the number of moles increases. Who‘s law is this? I_ ‘ to: e a. Pauli’s r“: it :3, ' l b. Charles‘s ‘* - T . . 5 ~ @ . BoyEe's w" ‘30:?“ . . t . Avogadro's .— ' \l ,_ \l f / . O“ 23 r 'N ' ‘- 17. A gas is contained in a flexible, 4.7 L container. The temperature of the gas is increased from 25 0C to 50 OC, and the pressure is decreased from 760 Torr to 730 Torr. What is the new volume of the gas? a?“ I (“glean w KOBE) is so i >6 f w. w ,oam. 3.3 @ 9.7 i. c. 5.8 L d. 6.5 L 18. 3.5 grams of a gas is held in a 1.13 i. container at 25 c’C and 2 atm. What is the molecular weight of the gas? Which molecole could this gas be? :1 :3 31222 2; @Li .8) :QQQOg uncle?) 3'5 :“‘m””’55 4 g/moi; He 38 g/mol; F2 ‘I . .' ‘Z'a/k ,w _. 19. If the reaction goes to completion, what-is the" m,a'xinju§n_,nun}ber of moles that'can be obtained by reacting 5.00 L of H2(g) "with 2".0‘0 L’AOfI.N2(g}’? AssumeSTP for the reactants and products. 5’ -' _ ,' re, . ..' . ' . - -' 3H2+N2~42NH3 "W .- Z'ZzLi 20. If molecuie A has a moiecuiar weightbf 127.5 g/rnol and. molecule B has a molecular weight of 120.2 g/moi, how many times-faster wili molecule B travel theta-molecule A? .1.30 ' l _ K. . , '2 g, . C. .973. I \173 I. [U I. w W V d. .943 01¢) 4 21. Rank the foliowiunggga as from gost to least édeai in terms of the van der Waai r coefficient b: co, N20, ti ,Hzogfi \0 :- gem/w, .. a was 0 HF > co > N20 > H202 H202 > HF > CO > N20 3. HF > CO > H202> N20 \l. ,_ if}. 4.co>er>H202>Nzo M p \I m "L ‘22. Which of the combinations of V, n and “i” below‘would behave the most ideally? \w; \Ql‘ifim‘fij WWW Ewich of the foliowing best expiains aii intermolecular forces? lectrostatic attractions between opposite charges. . The capacity of molecules to form instantaneous dipoles. 3. The tendency of ions to arrange themselves in lattices. 4. The large charge density that occurs when hydrogen is bonded to a very electronegative atom. 24. Which of the foilowing species exhibit hydrogen bonding? I. cage .1 II. CH30i-i \/ III. CH3COOH \/ 1. I only 2. II only 3. III only 4. I and II I and III II and III 7. I, II and III 2,5. For whichnoi= the folEowing species are London forces significant? 1. NHg WW \ 2. CH2F‘2 . W 3.03 (561W «-—~. C, ( 4-. SF6 \ 26. Which of the foElowing describes a fiuéds abiiity to resist flow? muciiage iscosity 3. surface tension 4. capilEary action _ 5. vapor pressure R29 '7 9:32: 7 ,0 ll? 2nk the foilowing species from highest to Eowest vapor pressure: HF, H20, NH3l K H3>HF>H20 r £535 3-5“ F > H20 > NH3 9W" 1+ e 3. H20 > NH3 > HP; 4. NH3 > H20 > HF ‘i huerQfiW-‘r 28. Rank the following species from Seast to greatest viscosity: CH4, C4H10, CH3F, CF4. . CH4 < C4H1o < CH3F < CPA, . CH4 < C4H1o < CF41r < CH3F . (341410 < CH4 < CH3F < (2ch . CHsF < C4H10 < CH4 < CFc; . C4H10 < CH4 < CF4 < CH3F m-waH 29. Rank the following species from highest to lowest boiiing point: HzTe, H25, H20, ste 1. H20 > H28 > ste > HzTe ' 2. H2O > ste > H2Te > H25 3. H20_>.H2Te.> H25? H2563 4..H20 > HzTe > H25e 3» H25 30. Which of the specieshelow is not covalent network? 1. graphite dry ice ' (‘V @6iamond® 4. quartz ...
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TA Practice Exam 2 - A} ow, {Mm CC &amp;lt; NH &amp;lt;...

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