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Unformatted text preview: Burke {jpb2376) m Homework 6 —Sutcl.ifl'c- (53320) 1 This printout should have 20 quwtions. Mifitiple-aholce questions may continue on the next; column or page w find all choice; before answering. 001 10.0 paws The Con-(rel. name for l‘lBr05(aq) 'm I. hydrobromic acid. 2. {301.1150 acid. correct 3. brommxs acid. 4. perbromlc acid. Explanation: 113:0; is barode acid. Bramam acid has one fewer oxygen atom than the "—ic" acid HBrOg. Pcrbromfc mild has one more oxygen atom than the “do” acid and has the formula “1310.1. Hydrobromic acid is an aqueous to lunch of hydrogen bromide (HBr). 002 10.0 points Which of these compounds would you export to ha 3 Weak electrolyte? 1. All of these compounds are strong elem trolytes. correct 2. calcium chloride 3. ammonth phmhate 4. imlfim'c acid Erharinm hydroxide Explanation: 003 10.0 winks How mam! mam of CaBrg are noodcwl b0 prepare 4.65 L of a 165 M solution? 4. 122 g 5. 0.173.; 6. 71105: correct: Explanation: M=7.65M 4,651.. 7.65 mol CaBr; 750.13g» M4155 Lx W x 2BDgCaBr2 1 mo! w 7110;; 004 10.0 points Thomas floured 25 mL of 0.50 M HG! intoa large. bottle. He then added enough water so {3131:0119 new (diluted) macaw-alien was 0.10 M HCl. How much water did Thomas add? I. 75 mL ‘2. 59 ml. 3. 150 ml. 4. 125 m}. H. 100 m1. com¢ 3. 25 m]. Explanation: M1=0.50M Vls=25mL Mg m 9.10 M M1 V1 m Mal/2 w M: V; m 0.5{25mL} V“ “ M2 " 0.1 m 125 ml. 125 mLis the FINALvolumeofthe diluted solution. The starting amount was 25 ML, so 1. 0.00303 g Thomas ADDED 100 mL to Lhc 25 mL toch the 125 ml. mud. 2. 5.20 g 005 10.0 paints 3. 4276 g Predict the products of the reaction bun-lie (31023“) - Homawork 6 - Subciilfe - (53130} 3 Explanation: 1 1 12:1le TWISDC+2T3¢¢291K —— oc — V = 1 E. a 4.39 I.” Mum/moi? VMW ‘ 020.051 L/mol \a‘MW o: f- . '2 Thus (P+¥)(V—nb)wnRT 2 * 3.1 P : nRT _ u '" EA: V —— :16 V1 a m (1 mo[)(0.03206 REL-{mom K) Mm, ‘ 1 1. w (1 mol)(0.051 um) "" (7 73 , )2 W (1 momma L2 . aim/1nd“! m (39.05 g/mol) (1 L)2 (5-13 mm) x 20.785? m. m 62.502? g/mot. The max; corrmpcrmis to the mam of the empiricai formula, 00 fllemolocular l‘omcfla is CfllsC’l. 009 10.0 points Gas X has a hum-x wdme than Gm; 1’ {ur film van der Waals come-am "a". This indicates that i. the molecules of gas X repel other X molecules. 2. the molecules of gas K have a higher velocity than do the molecules ofgas Y. 3. the molecules of X have meager inborn molecular attractions for each othm than the molecules of Y have for each other. cor-mat. 1!. the malacqu of X are larger than the moleculefi of Y. Explanation: 010 10.0 points {lac the van dcr Wnals‘ equation to calculate the pnmurc exerted by l moi of acetyicne at 18°C in a 1 L container. The van de: Waals constants for acetylene area 4.39 L?- ammo?1 and b m 0.051 Limo}. Correct answer: 20.?851‘ atm. 1311 10.0 points Under which of the following conditions is a real gas most likely to deviato from ideal behavior? 1. Kit is n notxlc gas 2. new moon 3. 'lhemlays and Thursdays 4. 20m premix-c 6. low density 6. low pro-sure 7. low temperature corn-d. 8. high volume Explanation: Deviations from idealélzy occur due 2:0 molecular attractions ur repulsion)". More attractions or repulsims can 0am:- wlim {he molecules are closer together. Low prmn‘e, 111(51 volume, and low density all correspond to molcculls being far apart. Low tampon attire ofinn nonmpondfi to molecules being close togethm. [1. also corresponds to low M netic may Willa: allow molcmflcs to 'stlck tone-the? easier. burly.- (jpb2376) — Homework 6 —- Sutclifi‘e - (53120) 2 [-lN03(aq) + Kflflaq) a; . 1. KHCI; 2. CiNOa, K20 3. KB, NOgCl 4. I{N03,HCI correct Explanation: This reaction of two miuhle compounds in aqueous soludion will be a metathesis mm:- aéon. The positive ion from one compomd comlfince; with the negative ion from the othm compound and vlccwersa. The products will be K'Nm and Hci, both aoluble compounds. 006 30.0mm idmfify the WW lama) for this reaction occuring in water: Barium perchlorate and sodium sulfate are mixed to form sodium pen (Mouth: and barile Mate. !. Na" and (210' 2. Na‘ and 010;; met 3.1m only 4.10.9“, 5014;, 1332*, and (:10; 5. $03" and 13.." 6. Ba“ only 7. 073+. $03.: and 010; Explanation: 007 10.0 points At constant temperature, the mm of elTuslon of fly is Lchofthexe 4. oneulzall‘ that of helium gas. 5- wwl‘owth that of oxygen gas. Explanation: Rate of efluaiouoi 02 w .mqu Bateof eflusionof Hg M .ffifiwox 130“... 2 1 Egg: 1. 0,25 r: d E l3le = :1‘ m2]: 603 10.0 points The composition of a compound used to make pclyfinyl d'nlon'de {PVC} is 33.4% C, 4.8% H and 56.8% C] by mam. it took 7.?3 min for a given volume of the compound to ef- flm through a porous plug, but it took only 6.18 min for the same amount of Ar to diffusn at nine mum: mnpuraturc and measure. What. is the molecular formula of the compound? 1.011301 2. Cal-[30! correct ‘ 3. 0311.01 4. CQHJLCl: 5. C4HECls 6. c.1115le Explanation: Ew7-73nfin he“. "45.181711: V: =1: 1 L VA, "—1- 1 L lll'fi'll'k,r at 39.95 g/mnl Elmeml analyses give an mnziirimi for 1110.13 of (021130;)fl. This formula mass ls 62.49 g/mol. V o< :1. (and IX molwdes of 933 that. cfl'us-e). 2. four times that. cf oxygen [.55 coma; The volumes are theme, so Eff ac g.“ . 1 3. twicethat ofbcllum gas. 1‘ '6 also We Wm 39? ac 37W. so burke 0bb2376) — Homework 6 “Sutcfiffew (53120) 4 012 10.0 points What Would be the mast Significant type of intermolecular forms in a liquid sample. of final-0mm: {CHF3)? I . dispmsion 2. comet 3. dipole-dipole: non-ed; 4.302111: 5. hydrogen bonding Explanation: London forms, dispersion forces, van der Waalc or induced dipole-5311 describe the same inWmolaczfla-r force. London forces are in— duced. diamliwd, and very weak. Moleculvs and atoms can invariance London forces be cause they lava electron clouds. London forces remit from the distortion of the eleo~ tron cloud of an atom or molecules by the presence of nearby atoms or molcmfles. Parmanent dipolmiipole irate-actions are stronger than London forces and occur ho twcm polar mlmr. molecules due f0 charge separation. H-bonds are a special case.- of vary among dipole-dipole inmactlona. They only occur wluza H is bonded to small, highly electroncg- 3|:ch atoms - F, 0 or N only. Ion—ion unmadions are fliesllrongest due to extreme charge separation and occur bawaen ionic moicmles. il'lwy can be thought of as both énw— and intramolecuhr handing. CHFg is a polar molecule that (1065:1012 con— taln H bonds; thucfote, dipole-dipole for-ca; will hethe mostxlmilicam. typo of intern-101w uln- forces present. 013 10.0 points Which of the {allowing slamming: about dis pinion form is NOT ecu-mt? Dlwersitm forces. 1. are the chy forces E)an nonpolar moleculue. 2. are also called London forces. 3. are temporary rather than permanent dipolwdipole interactions. 4. decrease in strength with increasing molecular aim. correct Explanation: Polarizabliity incrmm with increasing m of molecules and therefore wlth mamas- ing numbers of ulwtmrxs. Therefore, {om dun forces are generally manger for molecules that am larger or have more electrons. 014 10.0 mm Comidcr the two water molecular. . '6' A Which subanent is «arrest? 1. The hydrogen bond 8 is manger than the covalent bond A. 2. The lwdrogm band A is manger than the covalent bond 33. 3. ’E‘he covalent bond B '15 stronger than the hydrogen bond A. 4. The covalent board A is stronger than the hydrogun bond B. correct Explanation: 5? a” n /0 \“ A ‘3": m / H ll 6‘— 6—- A is a covalcnt band wiiile 13 is; a hydrogen bond. Covalent bonds are murfla stronger than Hnbon ds. burke pr2376} — Homwork 6 ~Sutcliffe— (53120) 5 015 10.0 minis ch of the} following moles-111m choon _ ) CHgOCii; CH;C£lO HgCRgOH are likdy mfimn lwdrogrm i" -“ 1' C and I) only 2. A anti B only 3. A anti D only correct 4. B anti D only 5. Another combination of compounds 6. B and C only 7. All are likely to form hydrogen bonds. 8. None forms hydrong bonds. 9.AandConly Explanation: Only molemfltfi with H attached be Lhc electmncgatim atoms N, O, and P can hy— drogen hem}. Of the 114039le given, only CHSCOOH and CligClbOH have hydrogen attached to oxygen, :90 than are the only ones that ml: undergo hydrogen bonding. 016 10.0 paints List the 3359:: H2, (133?, N2, CR1, ii]? in order of DECREASING tendency to behave m kiwi gases. (Comm-3r only immunolde Forces in determining non-ideallay.) 1. Hz, HF, N2, CligF, CF; 2- H2. 3335‘, N2. CR1, HF 3. HI“. Casi-5‘, cm, N2, H2 4. H2, N2, CF.“ Cl‘lgF‘, HF correct: 5. (ll-‘4, CHaF, N2, HF. H2 Explanation: The strolurer the inl‘wawlecula: ibrccs present, the 5mm [he mitleality: InducedDipole Hg Wallabmostideal N: 1 CR1 Zugml Dipolemdlpoie CH3? I'leondim; ill“ has! idea] 517 10.0 points Because the forces acting on molecules at. the sun-fact: of a liquid are not. equal in all (Eh-w Lions, 'an liquid mdnibih: a property 35mm». as I. capillary action. 2. all-face Muslim. marred 3. density. Explanation: Molecules on the mxfl'acc of a liquid are influenced by intermolecular attractions to- waxds the interior; Lhasa «uranium pull the muffle layer Ward the center. The moststa» ble situation is one in which the surface area is For a five]: vellum, a. uphere has the least pmfihln maxim arm. Surface Won is a measure cf the. inward form that must be ovmome to expand the swim nl‘a liquid. 018 10.0 points A liqu'ui in 3 test tube has, a curved smface swab that the edges ta:ch the glass are bladder than the surface at the center. This must mean that the cohmfive forces are less than the adhesive forces. 1. ’zhxe correct: 2. Palm Explanation: This is the typical meniscus shape of wan in: in glass - a concave shape. The liqfiid tries to maximum Its contact with the glass became the adhesive fax-cm are stronger than the cohesive forums. hmke $52376) m Homework 6 ~- Sutclifie - (53120) 019 10.0 poinm Which would you expect. Do be least viscous? 1. Cglla at 39°C 2. Callla at 39°C 3. (Ed—la at 50°C correct 4. CsHia 3!. 50°C Explanation: 020 10.0 pointfi For which of the following is the type of solid INCORRECTLY givm? 1. Cal. wmlent solid correct 2. K?, ionic solid 3. £120, molecular solid 4. Ni, metallic solid 5. Cells. molecular soliti Explanation: $1 is an ionic solid. An ionic. how is a bond between a cation UK”) and an anion {1"}. ...
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This note was uploaded on 03/24/2010 for the course CH 301 taught by Professor Fakhreddine/lyon during the Fall '07 term at University of Texas at Austin.

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Homework 6 - Burke{jpb2376 m Homework 6 —Sutcl.ifl'c(53320 1 This printout should have 20 quwtions Mifitiple-aholce questions may continue on

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