Fall 05 MT Solns - E51122? — ENGINEERING STATICS — '...

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Unformatted text preview: E51122? — ENGINEERING STATICS — ' MID-TERM EXAM November 3“, 21.1115 {1:31} pm — 4:31] pm} Question 1 A prcczisl—L‘nncrale wall HECEiE‘rI‘L is lempflrarily held by the cables shuwn in Figure I. Knnwing the tension is 42m} H in cable AB and fiUflU N in cable AC, dalemuim: the magnitude and dircctiml of thc resuIlanl 0f 1h: [areas exerted by Cables AB and AC un stake A. Clix-t 5;qu anhwur in tcrmH Ofa vuclnr and in the [mm M magnitude and unmpnnunt angltfi. a. H 5.5m 11:5 r4250“ , TH -" “’00” “K y (p-ordunatles.‘ Fir (“55: fig) B( ain’t” “EB”;’,05 C(-—|5.'5,D,4 “pi”: Jig I\_ ,. a A .- " — . a a" n A A A h..— :f-L To' -31 #191 4 ‘H: “uh I-voJAA'L 012‘“ 3 '3 vna(4m”) = [37-09 f -31c-o:f + lbflDE] rd :. ‘HM {Loonfi):E40m$ ‘4‘)0‘5’3 *qufl Emmi -"112.D0j‘ 4.35.5021” HEEL":- E250“! CUWJ mam CD5 E9}; i-qmu =3" '53: IE!“ — 9'15 0 FTTL {fl 3—H EL gL C05 9;: 3"?” E 92.1:- é‘fhlfi .6150. - ESflllY — ENGINEERING STATICS — MID-TERM EXAM November 2E, 2005:1931] am -12:3l} pm} Name {print}: [I]: Questian 2 Replace the couple moments and farces acting an “JUN - m the pipe aSSernlzrlj,r by an equivalent resultant feree r and eeuple moment aeting at the paint 0, expressing year answer in Cartesian veetnr netatian. RESLRKNW)‘; Fort}: Ch Pea-fr Q Farce cg? Fl Farce 623 B A - e. up. $3 : 219K) C0545 T = we) emits lain: P. . ‘ inn-Li“. a “phlegm Farce, Cir, C A r: E: = Wst Rflfiulllmj‘l ‘93 rag; .1 4L J- ‘ (3013M +(im-Lw “ll-l-l'll-k) + (1.3%) 5 Elm”: "' “303 + ifie-elgn Pfleefibimli gawk mama-ea cit pan-ll ‘0 COuplfi mewfi (:3 Pi Cgmfla mewfi‘l oi 53'? _\ I A h We - mmm film = iiaemiis"; - leesmuSkEN-W : 31232;} ‘lL‘l‘SZgN-m ESIJIEEY — ENGINEERING STATICS — MID-TEE}! EXAMI November 26, 2005 (9:31] am - 11:30 pm} Name {print}: ID: Questinn 2 gaunt: A mflmrfifi dam. "it: Fa Cbaufi $333th ‘0 VP] = (fig-5.3m ; A I' r- r_ h m = a: x. a: g * a ‘L = cameo» P" P'l fl ;_ EN A 0 Cr" ‘ '38} + O'k'. ‘3 C) 301:) A» = 156mm mflfhfl (121’me *6 1;?) Qkfi 1?,f5'yfilf ‘1) Ar" : rx E53 'A '2‘" A - 1L s ' _ I: ma : r15 " $15 # q H O “05 m L0 — (mam-Lg 1c. 1 I I A : #1556}? #15561 WW?) “HUM (kw-:3 X“: E: Vdnr-{H‘ leaggmfifl "uryri EM mm“ ‘34: 1a; 92W“: +3” *wflufg“ C}. Q‘ESLE‘KDHAX gauge mgmfi' Ffir‘l?‘ : EEC *F 39" E . N :EUQQPL)+QLW3: - HLW‘STLY\*KEEOfi3+(-Hssléfi ‘ 599$ = Ema-‘1'} — tel-3123mm mm a) AWL. ESIJZIY — ENGINEERING STATICS — MID-TERM EXAM November 2a, 2005 [9:30 am - 12:31] pm} ID: Name {print}: Question 3 Romeo tries to reach Juliet by elimhing with constant velocity up a rope whieh is knotted at point A. Any of the three segments of the rope can sustain a maximum force of 2 kN before it breaks. Determine if Romeo, who has a mass of 65 kg, can elimh the rope without any of the three segments breaking. If so, can he along 1with his Juliet, who has a mass of 60 kg, elimh down the rope at constant veloeity without an},r of the three segments breaking. tab at the as a L. L 1:: ' g . "t: a F. on w W "r (1: h = ' J": Kim} : w _ 511*“: 6C}; _(ij Eta: Re meow CA one N=m5 = (says-ax) = ezsu 4 mi -- as ESflZZY — ENGHEERWG STATICS — MID-TERM EXAM November 26, Eflflfi [9:30 am - 12:31] pm} Name (print): ID: Question 3 gaunt: $“Wn QDHCU 'Ir : w FF“: 3 S‘IF'IE‘DQ “1&6 5036,33 63?; saw a: the: "-‘3K Sméifiu 2 mm < Amy-01¢ RU Wm M Euh'xcilV lrbgk‘xfl' w m5 = (as +éO}C'I-81 : iAlé‘N 4 1m *0“ Y'i‘fl-F‘h (30f?- ?r-Qm GOLF? $13.51 W ; ‘Ffic = $339 mg a“ finéfl I = HHEGfiéD ‘ Illfi Smé‘f = ‘HD‘EN 4 AIM OK ~“ lLLléN 4: MN non RQWEG Cam <fiw&n u? Efi- Wflfi1GW$ Pflwflg afl& 3m&fi Cm"! C‘fimub Abwn 39W: I'D-PG. E5022? — ENGINEERING STATICS u MID-'I'ERM EXAM November Elli, 21305 {9:311 am 42:31] pm] Name {print}: 1]): Question =1 Datermine the normal reaction at the roller A and 1016-“ horizontal and VETtiCI—il compuncnts at pm B for equilibrium at" the member Shawn. ESflEZY — ENGINEERING STATICS — MID-TERM EXEM November 26, 2005 {9:3l} am -12:3[l pm} Name {print}: ID: Question 5 The mobile erane is symmetrically supported by two outriggers at A and two at B in order to relieve the suspension ot‘the truck upon which it rests and to provide greater stability. If the erane and truck have a mass of £3 flflfl kg and eentre of mass at G, and the boom has a mass of 13th} kg and a centre of mass at 6;, determine the vertical reaetions at eaeh of the four outriggera when the boom angle 9 is 35" and the boom is supporting a load with a mass of 12W kg. For the same load, what is die critical boom angle for which the erane will be on the verge of tipping over? (Hint: consider what the vertical reaetion atA will be when the erane is on the verge of tipping over} IFBU 0'? mob-ilk: {ii—m 3 é'lgrn + 1 vi = (1102336380 = |i'"t"tki~1 . “A = (ieer-St) *‘ I‘i-éé an at .i : (i aeoo )(a - at) = Lets-aw. Eon-m (pg-35$: {it = 35% @Smfl r g “(£3500 +. (He-6X1) — (maxeafigsfli) “(H-"flXmlfiemas‘3—a) = e IO ESIIJEEY — ENGINEERING STATICS — MID-TERBI EXAM November 26, Zflflfi {9:31) am - 12:31} pm) Name (print): —— II}: Question 5 imam Fl E‘flb: L: I'I {:1 {FE = L‘dhfi‘m %€ Emma: 15 cur-1 II’Wj Ufl'gfi o? EFEPP-‘fifb Due; FF] :0 TCJAGLS Mbmcflfie ‘3') {Jim =0 Er (Ha-630) - (neefleamé’J-“Q -* (In-113(1L-Lssan‘3 4*) i 0 Same. = 135% 5450-1 -= Q'GrLL'hl Q: I “we,” I] GO ES'EIZZ'JI - ENGINEERING STA'I‘ICS — MID-TERM EXAM November 1s, Zflflfi (9:30 am 41:31] pm} Name [print]: 1]): Question 6 The horizontal beam shown in the figure is supported by springs at each end and loaded with an 80!] N force as shown. a} Determine the reaction forces acting at A and B. h} If the stiffness in spring A is ks=5 Lew-“m. determine the required stiffness of the spring at B so that 1when the beam is loaded 1with the Stilt] N force. it remains in the horizontal position. QDH Ji’p, ‘3 F6 1::5E:::::Zl" fifiio hater-4‘- {—‘h-‘lm —~e- { £Hkvo i: = Wt _ —8oe:(D + were it : MA * fa a!“ i a? K. KB W- 12 ...
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This note was uploaded on 03/25/2010 for the course ENGG ENGG 130 taught by Professor Axelpavillet during the Spring '10 term at Keyano College.

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Fall 05 MT Solns - E51122? — ENGINEERING STATICS — '...

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