solutions chapter 5

solutions chapter 5 - CHAPTER FIVE GASES 24. a. Containers...

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CHAPTER FIVE GASES 24. a. Containers ii, iv, vi, and viii have volumes twice that of containers i, iii, v, and vii. Containers iii, iv, vii, and viii have twice the number of molecules present as compared to containers i, ii, v, and vi. The container with the lowest pressure will be the one which has the fewest moles of gas present in the largest volume (containers ii and vi both have the lowest P). The smallest container with the most mol of gas present will have the highest pressure (containers iii and vii both have the highest P). All the other containers (i, iv, v and viii) will have the same pressure between the two extremes. The order is: ii = vi < i = iv = v = viii < iii = vii. b. All have the same average kinetic energy since the temperature is the same in each container. Only temperature determines the average kinetic energy. d. μ rms = (3 RT/M) 1/2 ; the root mean square velocity only depends on the temperature and the molar mass. Since T is constant, the heavier argon molecules will have the slower root mean square velocity as compared to the neon molecules. The order is: v = vi = vii = viii < i = ii = iii = iv. 29. 6.5 cm × cm mm 10 = 65 mm Hg = 65 torr; 65 torr × torr 760 atm 1 = 8.6 × 2 10 - atm 31. If the levels of Hg in each arm of the manometer are equal, the pressure in the flask is equal to atmospheric pressure. When they are unequal, the difference in height in mm will be equal to the difference in pressure in mm Hg between the flask and the atmosphere. Which level is higher will tell us whether the pressure in the flask is less than or greater than atmospheric. a. P flask < P atm ; P flask = 760. ! 118 = 642 mm Hg = 642 torr; 642 torr × torr 760 atm 1 = 0.845 atm 0.845 atm × atm Pa 10 013 . 1 5 × = 8.56 × 10 4 Pa b. P flask > P atm ; P flask = 760. torr + 215 torr = 975 torr; 975 torr × torr 760 atm 1 = 1.28 atm 1.28 atm × atm Pa 10 013 . 1 5 × = 1.30 × 10 5 Pa c. P flask = 635 ! 118 = 517 torr; P flask = 635 + 215 = 850. torr
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2 CHAPTER 5 GASES 34. The pressure exerted on the balloon is constant and the moles of gas present is constant. From Charles’s law, V
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solutions chapter 5 - CHAPTER FIVE GASES 24. a. Containers...

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