yindeemark (rry82) – Homework 5 – chelikowsky – (59005)
1
This printout should have 23 questions.
Multiplechoice questions may continue on
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beFore answering.
001
(part 1 oF 2) 10.0 points
A block oF mass
m
is accelerated across a
rough surFace by a Force oF magnitude
F
that
is exerted at an angle
φ
with the horizontal,
as shown above. The Frictional Force on the
block exerted by the surFace has magnitude
f
.
f
F
φ
m
What is the magnitude oF the acceleration
va
oF the block?
1.

va

=
F
cos
φ
m
2.

va

=
F
m
3.

va

=
F
cos
φ

f
m
4.

va

=
F

f
m
5.

va

=
F
sin
φ

m g
m
002
(part 2 oF 2) 10.0 points
Which oF the Following expressions For the
coe±cient oF Friction is correct?
1.
μ
=
f
m g

F
sin
φ
2.
μ
=
f
m g

F
cos
φ
3.
μ
=
m g

F
cos
φ
f
4.
μ
=
m g
f
5.
μ
=
f
m g
003
10.0 points
The suspended
m
1
mass on the right is
moving up, the
m
2
mass slides down the ramp,
and the suspended
m
3
mass on the leFt is
moving down. There is Friction between the
block and the ramp, with the coe±cient oF the
kinetic Friction
μ
. The acceleration oF gravity
is
g
and the acceleration oF the three block
system is
a
. The pulleys are massless and
Frictionless.
m
2
μ
θ
m
3
m
1
What is the equation oF motion oF the three
block system?
1.
m
3
g
+
m
2
g
(sin
θ

μ
sin
θ
)

m
1
g
= (
m
1
+
m
2
+
m
3
)
a
2.
m
3
g
+
m
2
g
(cos
θ

μ
sin
θ
)

m
1
g
= (
m
1
+
m
3
)
a
3.
m
3
g
+
m
2
g
(cos
θ

μ
sin
θ
)

m
1
g
= (
m
1
+
m
2
+
m
3
)
a
4.
m
3
g
+
m
2
g
(sin
θ

μ
sin
θ
)

m
1
g
= (
m
1
+
m
3
)
a
5.
m
3
g
+
m
2
g
(cos
θ

μ
cos
θ
)

m
1
g
= (
m
1
+
m
3
)
a
6.
m
3
g
+
m
2
g
(1

μ
)

m
1
g
= (
m
1
+
m
2
+
m
3
)
a
7.
m
3
g
+
m
2
g
(sin
θ

μ
cos
θ
)

m
1
g
= (
m
1
+
m
3
)
a
8.
m
3
g
+
m
2
g
(1

μ
)

m
1
g
= (
m
1
+
m
3
)
a
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2
9.
m
3
g
+
m
2
g
(sin
θ

μ
cos
θ
)

m
1
g
= (
m
1
+
m
2
+
m
3
)
a
10.
m
3
g
+
m
2
g
(cos
θ

μ
cos
θ
)

m
1
g
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 Fall '08
 Turner
 Acceleration, Force, Friction, Mass, Work, Normal Force

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