Homework 7-solutions - yindeemark (rry82) Homework 7...

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: yindeemark (rry82) Homework 7 chelikowsky (59005) 1 This print-out should have 10 questions. Multiple-choice questions may continue on the next column or page find all choices before answering. 001 10.0 points If the earth were of uniform density, what would be the value of g inside the earth at half its radius? (The value of g at the surface of earth is 9.8 m/s 2 .) 1. 39.2 m/s 2 2. 9.8 m/s 2 3. 4.9 m/s 2 correct 4. 19.6 m/s 2 Explanation: Consider the spherical shell idea: only the mass of the earth in the inner shell con- tributes to g ; the mass of the sphere of ra- dius r 2 . To determine this smaller mass, con- sider the effect on the volume: V r 3 , so V parenleftbigg 1 2 r parenrightbigg 3 = 1 8 r 3 ; 1 8 of the original volume means 1 8 of the original mass. Now G m r 2 , so G 1 8 m parenleftbigg 1 2 r parenrightbigg 2 = 1 8 m 1 4 r 2 = 1 2 m r 2 , and the accleration due to gravity at r 2 is g 2 . 002 10.0 points The planet Mars has a mass of 6 . 1 10 23 kg and radius of 3 . 2 10 6 m. What is the acceleration of an object in free fall near the surface of Mars? The value of the gravitational constant is 6 . 67259 10 11 N m 2 / kg 2 . Correct answer: 3 . 97488 m / s 2 . Explanation: Let : M = 6 . 1 10 23 kg , R = 3 . 2 10 6 m , and G = 6 . 67259 10 11 N m 2 / kg 2 . Near the surface of Mars, the gravitation force on an object of mass m is F = G M m R 2 , so the acceleration of an object in free fall is a = F m = G M R 2 = (6 . 67259 10 11 N m 2 / kg 2 ) 6 . 1 10 23 kg (3 . 2 10 6 m) 2 = 3 . 97488 m / s 2 . 003 10.0 points An apparatus like the one Cavendish used to find G has large lead balls that are 7 kg in mass and small ones that are 0 . 028 kg. The center of a large ball is separated by 0 . 055 m...
View Full Document

This note was uploaded on 03/26/2010 for the course PHY 303K taught by Professor Turner during the Fall '08 term at University of Texas at Austin.

Page1 / 4

Homework 7-solutions - yindeemark (rry82) Homework 7...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online