yindeemark (rry82) – Homework 10 – chelikowsky – (59005)
1
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beFore answering.
001
10.0 points
At
t
= 0, a wheel rotating about a fxed axis at
a constant angular deceleration oF 0
.
46 rad
/
s
2
has an angular velocity oF 0
.
9 rad
/
s and an
angular position oF 6
.
6 rad.
What is the angular position oF the wheel
aFter 4 s?
Correct answer: 6
.
52 rad.
Explanation:
Let :
α
=
−
0
.
46 rad
/
s
2
,
ω
0
= 0
.
9 rad
/
s
,
θ
0
= 6
.
6 rad
,
and
t
= 4 s
.
The angular position is
θ
f
=
θ
0
+
ω
0
t
+
1
2
αt
2
= 6
.
6 rad + (0
.
9 rad
/
s) (4 s)
+
1
2
(
−
0
.
46 rad
/
s
2
) (4 s)
2
=
6
.
52 rad
.
002
(part 1 oF 3) 10.0 points
As a result oF Friction, the angular speed oF a
wheel c hanges with time according to
d θ
d t
=
ω
0
e

σ t
,
where
ω
0
and
σ
are constants. The angular
speed changes From an initial angular speed
oF 4
.
81 rad
/
s to 3
.
31 rad
/
s in 3
.
92 s
.
Determine the magnitude oF the angular
acceleration aFter 2
.
75 s.
Correct answer: 0
.
352832 rad
/
s
2
.
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 Fall '08
 Turner
 Kinetic Energy, Mass, Work, Moment Of Inertia, Correct Answer, Icm

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