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Unformatted text preview: yindeemark (rry82) Homework 10 chelikowsky (59005) 1 This printout should have 7 questions. Multiplechoice questions may continue on the next column or page find all choices before answering. 001 10.0 points At t = 0, a wheel rotating about a fixed axis at a constant angular deceleration of 0 . 46 rad / s 2 has an angular velocity of 0 . 9 rad / s and an angular position of 6 . 6 rad. What is the angular position of the wheel after 4 s? Correct answer: 6 . 52 rad. Explanation: Let : = . 46 rad / s 2 , = 0 . 9 rad / s , = 6 . 6 rad , and t = 4 s . The angular position is f = + t + 1 2 t 2 = 6 . 6 rad + (0 . 9 rad / s) (4 s) + 1 2 ( . 46 rad / s 2 ) (4 s) 2 = 6 . 52 rad . 002 (part 1 of 3) 10.0 points As a result of friction, the angular speed of a wheel c hanges with time according to d d t = e t , where and are constants. The angular speed changes from an initial angular speed of 4 . 81 rad / s to 3 . 31 rad / s in 3 . 92 s . Determine the magnitude of the angular acceleration after 2 . 75 s. Correct answer: 0 . 352832 rad / s 2 ....
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This note was uploaded on 03/26/2010 for the course PHY 303K taught by Professor Turner during the Fall '08 term at University of Texas at Austin.
 Fall '08
 Turner
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