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# oldhw16 - hinojosa(jlh3938 oldhomework 16 Turner(58185 This...

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hinojosa (jlh3938) – oldhomework 16 – Turner – (58185) 1 This print-out should have 16 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 001 (part 1 of 3) 10.0 points A 2 . 7 kg particle moves along the x axis under the influence of a single conservative force. If the work done on the particle is 106 J as it moves from x 1 = 1 m to x 2 = 4 m, find the change in its kinetic energy. Correct answer: 106 J. Explanation: The change in the kinetic energy is equal to the work done: Δ K = W = 106 J . 002 (part 2 of 3) 10.0 points Find the change in its potential energy. Correct answer: - 106 J. Explanation: Since Δ K + Δ U = 0 , then Δ U = - Δ K = - 106 J . 003 (part 3 of 3) 10.0 points Find its speed at x 2 = 4 m if it starts from rest. Correct answer: 8 . 86107 m / s. Explanation: Using K = m ( v 2 end - v 2 init ) 2 we obtain v = radicalbigg K m = radicalBigg 2(106 J) 2 . 7 kg = 8 . 86107 m / s . 004 10.0 points A block of mass m slides on a horizontal frictionless table with an initial speed v 0 . It then compresses a spring of force constant k and is brought to rest. The acceleration of gravity is 9 . 8 m / s 2 . v m k m μ = 0 How much is the spring compressed x from its natural length? 1. x = v 2 0 2 m 2. x = v 0 m k g 3. x = v 0 m k g 4. x = v 0 radicalbigg m g k 5. x = v 0 radicalbigg m k correct 6. x = v 0 radicalbigg k m 7. x = v 0 m g k 8. x = v 0 radicalBigg k m g 9. x = v 2 0 2 g 10. x = v 0 k g m Explanation: Total energy is conserved (no friction). The spring is compressed by a distance x from its natural length, so 1 2 m v 2 0 = E i = E f = 1 2 k x 2 , or x 2 = m k v 2 0 , therefore x = v 0 radicalbigg m k . Anyone who checks to see if the units are correct should get this problem correct.

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hinojosa (jlh3938) – oldhomework 16 – Turner – (58185) 2 005 10.0 points A bead slides without friction around a loop- the-loop. The bead is released from a height of 12 m from the bottom of the loop-the-loop which has a radius 4 m.
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oldhw16 - hinojosa(jlh3938 oldhomework 16 Turner(58185 This...

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