# oldhw19 - hinojosa (jlh3938) oldhomework 19 Turner (58185)...

This preview shows pages 1–2. Sign up to view the full content.

1 This print-out should have 12 questions. Multiple-choice questions may continue on the next column or page – fnd all choices beFore answering. 001 10.0 points The planet Mars has a mass oF 6 . 1 × 10 23 kg and radius oF 3 . 4 × 10 6 m. What is the acceleration oF an object in Free Fall near the surFace oF Mars? The value oF the gravitational constant is 6 . 67259 × 10 - 11 N · m 2 / kg 2 . Correct answer: 3 . 521 m / s 2 . Explanation: Let : M = 6 . 1 × 10 23 kg , R = 3 . 4 × 10 6 m , and G = 6 . 67259 × 10 - 11 N · m 2 / kg 2 . Near the surFace oF Mars, the gravitation Force on an object oF mass m is F = G M m R 2 , so the acceleration oF an object in Free Fall is a = F m = G M R 2 = (6 . 67259 × 10 - 11 N · m 2 / kg 2 ) × 6 . 1 × 10 23 kg (3 . 4 × 10 6 m) 2 = 3 . 521 m / s 2 . 002 10.0 points An object has a weight W when it is on the surFace oF a planet oF radius R . What will be the gravitational Force on the object aFter it has been moved to a distance oF 4 R From the center oF the planet? 1. F = W 2. F = 1 4 W 3. F = 4 W 4. F = 16 W 5. F = 1 16 W correct Explanation: On the surFace oF the planet, W = GM m R 2 . When the object is moved to a distance 4 R From the center oF the planet, the gravitational Force on it will be F = GM m (4 R ) 2 = GM m 16 R 2 = 1 16 GM m R 2 = 1 16 W . 003 (part 1 oF 3) 10.0 points Consider a solar system similar to our Sun, Earth, and Moon. Moon Planet Sun By what percentage does the weight oF the 60 . 3 kg woman standing in a total eclipse oF the Sun (oF mass 1 . 979 × 10 30 kg) decrease due to the Sun’s gravitational Force (neglect- ing the Moon’s gravitational Force) when com- pared to her weight due to the planet’s mass (4 . 21 × 10 24 kg) alone? The radii oF the planet and its moon are 6 . 57 × 10 6 m and 7 . 59 × 10 22 kg, respectively, the distances oF the planet From the Sun and the moon are 1 . 403 × 10 11 m and 3 . 49 × 10 8 m, respec- tively, and the universal gravitational con- stant is 6 . 67259 × 10 - 11 N m 2 / kg 2 . Correct answer: 0

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

## This note was uploaded on 03/26/2010 for the course PHY 303K taught by Professor Turner during the Fall '08 term at University of Texas.

### Page1 / 5

oldhw19 - hinojosa (jlh3938) oldhomework 19 Turner (58185)...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online