2007 BICH 441 1st Exam

2007 BICH 441 1st Exam - name...

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Unformatted text preview: name ________________________________________ BICH 441 EXAM 1 February 16, 2007 An Aggie does not lie, cheat, or steal, or tolerate those who do. I swear on my honor as an Aggie that I have not received or given unauthorized aid on this exam, and I am not aware of others who have received or given unauthorized aid on this exam. signed _________________________________________________________ NO CALCULATORS! Before you begin, write your name on each page (there are 5 pages) and sign the Aggie Honor Code statement above. Information you may find useful in answering some of the questions: fructose-1,6-bisP + H 2 O → fructose-6-P + P i ∆ G°' = –13.3 kJ/mol 1,3-bisphosphoglycerate + H 2 O → 3-phosphoglycerate + P i ∆ G°' = –49.4 kJ/mol PEP + H 2 O → pyruvate + P i ∆ G°' = –62.2 kJ/mol glucose-6-P + H 2 O → glucose + P i ∆ G°' = –13.8 kJ/mol citrate → isocitrate ∆ G°' = +6.7 kJ/mol glucose-6-P → fructose-6-P ∆ G°' = +1.67 kJ/mol ATP + H 2 O → ADP + P i ∆ G°' = –30.5 kJ/mol R = 8.314 J/mol•°K assume T = 25°C Questions 1-15 (2 pts each). Enter your answer on your Scantron sheet. 1. ∆ G°' for the reaction in glycolysis catalyzed by phosphoglycerate kinase is: A. –49.4 kJ/mol B. –18.9 kJ/mol C. 30.5 kJ/mol D. 49.4 kJ/mol 2. K eq ' for the sum of the reactions in the TCA cycle is 1.0 × 10 7 . ∆ G°' for this series of reactions is therefore: A. –40 kJ/mol B. –20 kJ/mol C. –1 kJ/mol D. 10 kJ/mol 3. K' eq for the reaction in the TCA cycle catalyzed by aconitase is: A. 1 × 10 –4 B. 0.07 C. 1.2 D. 15 4. The molecule shown is part of the reaction mechanism of: 4....
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This note was uploaded on 03/27/2010 for the course BICH 441 taught by Professor Staff during the Spring '08 term at Texas A&M.

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2007 BICH 441 1st Exam - name...

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