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Unformatted text preview: Name: ___________________________ UIN: _____________ Biochemistry 441 Section 505 Quiz 1 No calculators! Show all work. 1. Consider the net reaction: Glucose 1-phosphate Fructose 6-phosphate Using the following information: Glucose 1-phosphate Glucose 6-phosphate G' = - 7.3 kJ mol-1 Fructose 6-phosphate Glucose 6-phosphate G' = - 1.7 kJ mol-1 R = 8.315 J mol-1 K-1 T = 25C (a) (2 points) What would the standard free energy be for the net reaction? Show your work and units! ANSWER (a) The last reaction will be reversed so that glucose 6-phosphate can be cancelled. The G' for that reaction will have to be multiplied by -1 to give + 1.7 kJ mol-1 . The net G' can then be calculated by adding the two G' from the two reactions. Glucose 1-phosphate Glucose 6-phosphate G' = - 7.3 kJ mol-1 Glucose 6-phosphate Fructose 6-phosphate G' = + 1.7 kJ mol-1...
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This note was uploaded on 03/27/2010 for the course BICH 441 taught by Professor Staff during the Spring '08 term at Texas A&M.
- Spring '08