HW Chapter 3 - c. Anaheim has mean of 48.3; sample variance...

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Lily Le _ QA 233 -002 _ Fall 09 HOMEWORK CHAPTER 3 Question 9 a. 422 b. 380 c. i = (85/100) x 15 = 13 so the 85 th percentile is 690 d. The data above suggests that 85% of users use 690 or less minutes and the company plan allows 750 minutes. Therefore, the company should reduce the minute in the monthly plan of subscribers. Question 19 a. The range = 60 – 28 = 32 b. The mean = (28+42+45+48+49+50+55+58+60) / 9 = 48.3 The sample variance = = 92.75 The standard deviation = 9.63
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Unformatted text preview: c. Anaheim has mean of 48.3; sample variance of 136; standard deviation of 11.66 Pomona has mean of 48.3; sample variance of 92.75; standard deviation of 9.63 This means Pomona has better air quality index than Anaheim Question 33 a. Mean = 9,14 ; Median = 8 ; Mode = 8 b. Range = 16 ; Standard deviation = 5,67 c. Wilma z-score= 1.56, which is smaller than 3 so it should not be considered an outlier. Question 51 a. 35 b. 24 c. 0.92...
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HW Chapter 3 - c. Anaheim has mean of 48.3; sample variance...

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