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Unformatted text preview: κ AE A = Q enc ε = σ b A ε (c) Substitute the Fields: Cancelling A and substituting the feld, pσ 2 ε κ Ppσ 2 ε P = σ b ε σ b =σ 2 κ + σ 2 = σ 2 p1 κ + 1 P 2 σ b = . 1 μ C m 2 2 p1 3 . 2 + 1 P = 3 . 4 × 108 C / m 2 2 point(s) : Correct Sign 2 point(s) : Correct Value Total Points for Problem: 4 Points Solution to Lab Quiz Problem 10.2(Dielectric Constant from Field Map) Problem: The fgure to the right shows a dielectric slab in a uniForm electric feld. What is the dielectric constant oF the slab? Select One oF the ±ollowing: (a) (b) 1 (cAnswer) 2 (d) 3 (e) 4 Dielectric E κ E E Solution Since the feld is thinned by a Factor oF 2 , κ = 2 . 3 Total Points for Problem: 1 Points 4...
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 Spring '10
 Stewat
 Charge, Dielectric, Lab Quiz Problem, σt κ

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