mat-sln-asn-hwk22-spr02 - Solution for Homework 22 Optical...

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Solution for Homework 22 Optical Elements Solution to Homework Problem 22.1(Describe Image from MagniFcation) Problem: An image has magnifcation 0 . 5 . Which oF the Following describes the image? Select One oF the ±ollowing: (a) enlarged, upright. (b) enlarged, inverted. (c) reduced, inverted. (d-Answer) reduced, upright. Solution Since | m | < 1 , the image is reduced. Since m > 0 , the image is upright. Total Points for Problem: 2 Points Solution to Homework Problem 22.2(Old Master’s Trick) Problem: In the Physics oF Art Talk, some oF the Old Masters used a concave mirror to project the image oF a subject on a screen so they could trace the subject and get the perspective right. In the example the speaker presented, the object distance appeared to be about 10ft and the image distance about 3ft . Compute the radius oF curvature oF the mirror used. Report the radius with the correct sign. Select One oF the ±ollowing: (a) 9 . 3ft (b-Answer) 4 . 6ft (c) - 4 . 3ft (d) 2 . 3ft (e) Toby. Solution Apply the thin lens equation to fnd the Focal length, 1 s + 1 s = 1 f = 1 10ft + 1 3ft Solving For f gives f = 2 . 3ft . The mirror maker’s equation then gives r = 2 f = 4 . 6ft Total Points for Problem: 3 Points Solution to Homework Problem 22.3(Identify Virtual Image) Problem: Select the one oF the Following that is NOT a virtual image. 1
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Select One of the Following: (a) Image seen in mirror. (b) Image seen in magnifying glass. (c) Image seen through curved glass at aquarium. (d-Answer) Movie at the theater. Solution An image that can be projected is not virtual, so the movie you see on a movie screen is a real image. Total Points for Problem: 3 Points Solution to Homework Problem 22.4(Apparent Direction) Problem: The apparent direction of light is: Select One of the Following: (a) The direction to the object. (b) The path of the light ray. (c-Answer) Where light seems to come from. (d) All of the above since light moves in a straight line. Solution The apparent direction of light is the direction from which the light enters the detector or the direction the light exits to optical system. Total Points for Problem: 3 Points Solution to Homework Problem 22.5(Thin Lens Equation) Problem: A convex lens has focal length 50cm . An object is 60cm from the lens. Compute the location of the image. Select One of the Following: (a) 0 . 003cm (b) 27cm (c) - 27cm (d) - 300cm (e-Answer) 300cm Solution 2
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Apply the thin lens equation, 1 f = 1 s + 1 s 1 50cm = 1 60cm + 1 s Solve for the image distance, s = 300cm Total Points for Problem: 3 Points Solution to Homework Problem 22.6(What is an image?) Problem: What is an image? Select One of the Following: (a) The point where parallel light rays converge. (b) The point where a point light source must be placed to produce outgoing parallel rays.
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This note was uploaded on 03/29/2010 for the course PHYS 2469 taught by Professor Stewat during the Spring '10 term at University of Arkansas Community College at Batesville.

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mat-sln-asn-hwk22-spr02 - Solution for Homework 22 Optical...

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