{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

11_pdfsam_math 54 differential equation solutions odd

# 11_pdfsam_math 54 differential equation solutions odd -...

This preview shows page 1. Sign up to view the full content.

Exercises 1.2 –10 10 –0.5 0.5 C =2 C =1 C =0 . 5 C =0 C = 0 . 5 C = 1 C = 2 Figure 1–A : Graphs of the functions y = Ce 3 x + 1 for C = 0, ± 0 . 5, ± 1, and ± 2. 17. Differentiating φ ( x ), we find that φ ( x ) = 2 1 ce x = 2 (1 ce x ) 1 = 2( 1) (1 ce x ) 2 (1 ce x ) = 2 ce x (1 ce x ) 2 . (1.2) On the other hand, substitution of φ ( x ) for y into the right-hand side of the given equation yields φ ( x )( φ ( x ) 2) 2 = 1 2 2 1 ce x 2 1 ce x 2 = 2 1 ce x 1 1 ce x 1 = 2 1 ce x 1 (1 ce x ) 1 ce x = 2 ce x (1 ce x ) 2 , which is identical to φ ( x ) found in (1.2).
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern