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**Unformatted text preview: **y = 5 x 2 x 5 + C . Note: y 0 is also a solution to the original equation. It was lost in the Frst step when we divided by y 2 . 25. In this Bernoulli equation, n = 3. Dividing the equation by x 3 , we obtain x 3 dx dt + 1 t x 2 = t. Now we make a substitution u = x 2 to obtain a linear equation. Since u = 2 x 3 x , the equation becomes 1 2 du dt + 1 t u = t du dt 2 t u = 2 t 84...

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