Unformatted text preview: m ( t ) = m e kt . (3.2) In this problem, m = 50 g, and we know that m (3) = 10 g. These data yield 10 = m (3) = 50 · e k (3) ⇒ k = − ln 5 3 , and so the decay is governed by the equation m ( t ) = 50 e − (ln 5) t/ 3 = (50)5 − t/ 3 . After 4 days, the remaining amount will be m (4) = (50)5 − 4 / 3 g, which is (50)5 − 4 / 3 50 · 100% = 5 − 4 / 3 · 100% ≈ 11 . 7% of the original amount. 113...
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 Spring '10
 Hald,OH
 Math, Differential Equations, Linear Algebra, Algebra, Equations, Radioactive Decay, Harshad number, decay, radioactive substance, Initial Mass

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