Unformatted text preview: . Solving the ±rst equation For KX we arrive at KX = − ln ± 34 . 5 − 16 21 ² = 0 . 12675 . (3.8) Substituting this value into the second equation we, can solve For K as Follows: 33 . 7 = 16 + 21 e − . 12675 − K ⇒ K = − ³ . 12675 + ln ± 33 . 7 − 16 21 ²´ = 0 . 04421 . This results in an equation For the body temperature oF T ( t ) = 16 + 21 e − . 04421 t . ²rom equation (3.8) we now ±nd the number oF hours X beFore 12 Noon when the person died. X = . 12675 K = . 12675 . 04421 ≈ 2 . 867 (hours) . ThereFore, the time oF death is 2 . 867 hours (2 hours and 52 min) beFore Noon or 9 : 08 a.m. 118...
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 Spring '10
 Hald,OH
 Math, Differential Equations, Linear Algebra, Algebra, Equations, 2 hours, 1 hours, EKT, 2.867 hours, 52 min

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