Unformatted text preview: . 981) t + (0 . 0981) e − 10 t − . 0981 = 1000 , which gives ( t is nonnegative!) t ≈ 1019 . 468 ≈ 1019 sec. 3. ±or this problem, m = 500 kg, v = 0, g = 9 . 81 m/sec 2 , and b = 50 kg/sec. We also see that the object has 1000 m to fall before it hits the ground. Plugging these variables into equation (6) on page 111 of the text gives the equation x ( t ) = (500)(9 . 81) 50 t + 500 50 ± − (500)(9 . 81) 50 ² ( 1 − e − 50 t/ 500 ) 124...
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 Spring '10
 Hald,OH
 Math, Differential Equations, Linear Algebra, Algebra, Equations, Harshad number, Standard gravity, initial condition, Air resistance force

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