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Unformatted text preview: v ( t ) = 95 . 65 + Ce t/ 10 . Since v (0) = 0, we Fnd C = 95 . 65 and, hence, v ( t ) = 95 . 65 95 . 65 e t/ 10 . Integrating yields x ( t ) = 95 . 65 t 956 . 5 e t/ 10 + C 1 . Using the fact that x (0) = 0, we Fnd C 1 = 956 . 5. Therefore, the equation of motion of the object is x ( t ) = 95 . 65 t 956 . 5 e t/ 10 956 . 5 . To determine when the object is traveling at the velocity of 70 m/sec, we solve v ( t ) = 70. That is, 70 = 95 . 65 95 . 65 e t/ 10 = 95 . 65 ( 1 e t/ 10 ) t = 10 ln 1 70 95 . 65 13 . 2 sec . 128...
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This note was uploaded on 03/29/2010 for the course MATH 54257 taught by Professor Hald,oh during the Spring '10 term at University of California, Berkeley.
 Spring '10
 Hald,OH
 Math, Differential Equations, Linear Algebra, Algebra, Equations

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