177_pdfsam_math 54 differential equation solutions odd

177_pdfsam_math 54 differential equation solutions odd - |...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
Exercises 4.2 31. Using the trigonometric identity 1 + tan 2 t sec 2 t , we conclude that y 1 ( t )=tan 2 t sec 2 t ≡− 1 y 2 ( t ) 3 ( 3) y 1 ( t ) , and so y 1 ( t )and y 2 ( t ) are linearly dependent on (0 , 1) (even on ( −∞ , )). 33. (a) True. Since y 1 ( t )and y 2 ( t ) are linearly dependent on [ a, b ], there exists a constant c such that y 1 ( t )= cy 2 ( t )(o r y 2 ( t )= cy 1 ( t )) for all t in [ a, b ]. In particular, this equality is satisFed on any smaller interval [ c, d ], and so y 1 ( t )and y 2 ( t ) are linearly dependent on [ c, d ]. (b) ±alse. As an example, consider y 1 ( t )= t and y 2 ( t )= | t | on [ 1 , 1]. ±or t in [0 , 1], y 2 ( t )= t = y 1 ( t ), and so y 2 ( t ) c 1 y 1 ( t ) with constant c 1 =1 . ±or t in [ 1 , 0], we have y 2 ( t )= t = y 1 ( t ), and so y 2 ( t ) c 2 y 1 ( t ) with constant c 2 = 1. Therefore, these two functions are linearly dependent on [0 , 1] and on [ 1 , 0]. Since c 1 6 = c 2 , there is no such a constant c that y 1 ( t ) cy 2 ( t )on[ 1 , 1]. So, y 1 ( t )and y 2 ( t ) are linearly independent on [ 1 , 1]. 35. (a) No, because, for t 0, y 2 ( t )= | t 3 | = t 3 = y 1 ( t ). (b) No, because, for t 0, y 2 (
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: | t 3 | = t 3 = y 1 ( t ). (c) Yes, because there is no constant c such that y 2 ( t ) = cy 1 ( t ) is satisFed for all t (for positive t we have c = 1, and c = 1 for negative t ). (d) While y 1 ( t ) = 3 t 2 on ( , ), for the derivative of y 2 ( t ) we consider three dierent cases: t < 0, t = 0, and t > 0. or t < 0, y 2 ( t ) = t 3 , y 2 ( t ) = 3 t 2 , and so W [ y 1 , y 2 ]( t ) = t 3 t 3 3 t 2 3 t 2 = t 3 ( 3 t 2 ) 3 t 2 ( t 3 ) = 0 . Similarly, for t > 0, y 2 ( t ) = t 3 , y 2 ( t ) = 3 t 2 , and W [ y 1 , y 2 ]( t ) = t 3 t 3 3 t 2 3 t 2 = t 3 3 t 2 3 t 2 t 3 = 0 . 173...
View Full Document

This note was uploaded on 03/29/2010 for the course MATH 54257 taught by Professor Hald,oh during the Spring '10 term at University of California, Berkeley.

Ask a homework question - tutors are online