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Unformatted text preview: A = 0 and A 1 = 1 / 6. Therefore x p ( t ) = t 3 e 2 t / 6 is a particular solution to the given nonhomogeneous equation. 23. The righthand side of this equation suggests that y p ( ) = s ( A 2 2 + A 1 + A ). We choose s = 1 because r = 0 is a simple root of the auxiliary equation, r 2 7 r = 0. Therefore, y p ( ) = ( A 2 2 + A 1 + A ) = A 2 3 + A 1 2 + A y p ( ) = 3 A 2 2 + 2 A 1 + A y p ( ) = 6 A 2 + 2 A 1 . 193...
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 Spring '10
 Hald,OH
 Math, Differential Equations, Linear Algebra, Algebra, Equations

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